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Simora [160]
3 years ago
13

When an ideal diatomic gas is heated at constant

Physics
1 answer:
ira [324]3 years ago
7 0

Answer:

Q=∆U+W

Explanation:

work done+ change in internal energy = heat supplied to change the internal energy

(1st law of thermodynamics)

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A baton twirler has a baton of length 0.36 m with masses of 0.48 kg at each end. Assume the rod itself is massless. The rod is f
AleksAgata [21]

Answer:

Part a)

When rotated about the mid point

\tau = 0.021Nm

Part b)

When rotated about its one end

\tau = 0.042 Nm

Explanation:

As we know that the angular acceleration of the rod is rate of change in angular speed

so we will have

\alpha = \frac{\Delta \omega}{\Delta t}

\alpha = \frac{2.4 - 0}{3.6}

\alpha = 0.67 rad/s^2

Part a)

When rotated about the mid point

I = 2mr^2

I = 2(0.48)(0.18)^2

I = 0.0311 kg m^2

now torque is given as

\tau = 0.0311 (0.67)

\tau = 0.021Nm

Part b)

When rotated about its one end

I = m(2r)^2

I = (0.48)(0.36)^2

I = 0.0622 kg m^2

now torque is given as

\tau = (0.0622)(0.67)

\tau = 0.042 Nm

3 0
3 years ago
The theory of plate tectonics describes _______.
natulia [17]
I believe the answer is C
8 0
3 years ago
Read 2 more answers
The magnitude J of the current density in a certain wire with a circular cross section of radius R = 2.11 mm is given by J = (3.
oksano4ka [1.4K]

Answer:

i = 2.84 \times 10^{-3} A

Explanation:

As we know that current density is ratio of current and area of the crossection

now we have

J = \frac{di}{dA}

so the current through the wire is given as

i = \int J dA

now we have

i = \int_{0.921R}^R J dA

here we have

J = (3.25 \times 10^8)r^2

now plug in the values in above equation

i = \int_{0.921R}^R (3.25 \times 10^8)r^2 2\pi r dr

now we have

i = \int_{0.921R}^R 2\pi (3.25 \times 10^8)r^3 dr

i = (2.04 \times 10^9) \frac{r^4}{4}

now plug in both limits as mentioned

i = (2.04 \times 10^9)(\frac{R^4}{4} - \frac{(0.921R)^4}{4})

i = (2.04\times 10^9)(0.07 R^4)

here R = 2.11 mm

i = (2.04 \times 10^9)(0.07 (2.11 \times 10^{-3})^4)

i = 2.84 \times 10^{-3} A

8 0
3 years ago
Which is the direction of in stantaneous velocity for angular path
Alexandra [31]

<em>Answer:</em>

<em>Right hand rule</em>

<em>Explanation:</em>

<em>The rule by which the direction of a rotational vector can be found: take your right hand, curl your fingers and stick your thumb straight up. If you let the curl of your fingers follow the path of the rotating particle or body, your thumb will point in the direction of the angular velocity of the body.</em>

3 0
3 years ago
A car’s velocity as a function of time is given by Vx (t) = α.t + β.t 2 , where α= 3m/s and β= 0.1m/s 3 . Calculate the average
s344n2d4d5 [400]

The definition of average acceleration allows to find the result for the average acceleration in the given time interval is:

          a_{average}= 1.5  \ \frac{m}{s^2}

Instantaneous acceleration is defined as the derivative of velocity with respect to time.

           a =   \frac{dv}{dt}

Where a is the acceleration, v the velocity and t the time.

They indicate that the speed of the car is given by the relation.

          v = α t + β t²

With α = 3 m / s and β = 0.1 m / s³

Let's make  the derivative.

           a = α + 2β t

Let's substitute

            a = 3 + 2 0.1 t

Average acceleration is the change in velocity in the time interval.  

          a_{average} = \frac{\Delta v}{\Delta t }

Let's find the velocity at the indicated time.

For t = 5 s

         v₅ = 3 + 0.1 5²

         v₅ = 5.5 m / s

For t = 10 s

          v₁₀ = 3 + 0.1 10²

          v₁₀ = 13 m / s

Let's calculate the average acceleration.

           a_{average} = \frac{13 - 5.5 }{ 10 - 5 }\\

           a_{average}= 1.5 \  m/s^2

In conclusion using the definition of mean acceleration we can find the result for the mean acceleration in the given time interval is:

           a_{average} =  1.5 m / s²

Learn more here: brainly.com/question/20057878

7 0
3 years ago
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