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4 years ago

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When is thermal equilibrium achieved between two objects?

1 answer:

bulgar [2K]4 years ago

3 0

It’s C for sure I took this awhile back but I still remember... so thermal equilibrium is when to object have the same temperature due to them touching and transferring temperature for example if we have two metal blocks and one them is hotter than the other when you put them together the heat transfers and makes them both the same temperature.

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A child uses a rubber band to launch a bottle cap at an angle of 37.0° above the horizontal. The cap travels a horizontal distan

zavuch27 [327]

Answer:

Initial velocity will be 1.356 m/sec

Explanation:

Let the initial speed = u

Angle at which rubber band is launched = 37°

Horizontal component of initial velocity $u_x=ucos\Theta =ucos37^{\circ}=0.7986u$

Time is given as t = 1.20 sec

Distance in horizontal direction = 1.30 m

We know that distance = speed × time

So time $t=\frac{distance}{speed}$

$1.20=\frac{1.3}{0.7986u}$

$u=1.356m/sec$

So initial velocity will be 1.356 m/sec

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3 years ago

Suppose a moving car has 2000 J of kinetic energy. If the carʹs speed doubles, how much kinetic energy would it then have?

Bond [772]

Answer:

option A

Explanation:

given,

Kinetic energy of the car = 2000 J

speed of the car is doubled

we know,

$KE_1 = \dfrac{1}{2}mv^2$

$2000= \dfrac{1}{2}mv^2$ ........(1)

now, speed of the car is doubled

v' = 2 v

$KE_2 = \dfrac{1}{2}mv'^2$

$KE_2 = \dfrac{1}{2}m(2v)^2$

from equation (1)

$KE_2 = 4\times \dfrac{1}{2}m(v)^2$

$KE_2 = 4\times 2000$

$KE_2 = 8000\ J$

Hence, the Kinetic energy would be equal to 8000 J.

The correct answer is option A.

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3 years ago

If we always drop the balls from 1-m

dusya [7]

Answer:

height

weight of ball

time of ball falling

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3 years ago

Sam is riding his bike and spots a sinkhole. He slows his bike from 14.0 m/s to 2.0 m/s on 6.0 seconds. What is the bikes negati

VARVARA [1.3K]

By definition, average acceleration will be:
a=(v(f)-v(i))/t
a=(2-14)/6=-2 (m/s^2)
________
-2(m/s^2)

4 0

3 years ago

Read 2 more answers

A 64.0 kg pole vaulter running at 10.2 m/s vaults over the bar. If the vaulter's horizontal component of velocity over the bar i

Lubov Fominskaja [6]

Answer:

h = 5.05 m

Explanation:

given,

mass of pole vaulter, m = 64 Kg

speed of the vaulter,V = 10.2 m/s

horizontal component of velocity in air, v = 1 m/s

height of the jump,h = ?

using energy conservation

$E_i = E_f$

$\dfrac{1}{2}mv_i^2 + m g h_i= \dfrac{1}{2}mv_f^2+m g h_f$

initial height of the vaulter is equal to zero.

$\dfrac{1}{2}v_i^2 = \dfrac{1}{2}v_f^2+gh_f$

$h =\dfrac{v_i^2-v_f^2}{2g}$

$h =\dfrac{10^2-1^2}{2\times 9.8}$

h = 5.05 m

height of the jump is equal to 5.05 m.

4 0

4 years ago