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DENIUS [597]
3 years ago
6

How long should a spring be stretched for it to store 45 J of energy? The force constant of the spring is

Physics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

x = 0.4 m

Explanation:

When a spring is stretched from its equilibrium position. Some energy is stored in the spring. This energy is called the elastic potential energy of the spring. The formula used to calculate the magnitude of this stored energy is given as follows:

P.E = (1/2)kx²

where,

P.E = Elastic Potential Energy Stored in the spring = 45 J

k = Spring Constant = 540 N/m

x = amount of stretching = ?

Therefore,

45 J = (1/2)(540 N/m)x²

x² = (45 J)(2)/(540 N/m)

x = √(0.167 m²)

<u>x = 0.4 m</u>

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Serggg [28]

Answer:

Centripetal acceleration.

Explanation:

Centripetal acceleration is a property of a body moving in a uniform circular path and it is directed radially towards the center of the circle in which body is rotating.

The force which causes this acceleration is centripetal force which is also directed towards the center of the circle and pulls the body towards its center.

It is calculated through following formula

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7 0
3 years ago
Consider two celestial objects with masses m1 and m2 with a separation distance between their centers r. If the first mass m1 we
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The new magnitude of the force of attraction will be 6 times the original force of attraction

<h3>How to determine the initial force </h3>
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F = Gm₁m₂ / r²

F₁ = Gm₁m₂ / r²

<h3>How to determine the new force </h3>
  • Mass 1 = 2m₁
  • Mass 2 = 3m₂
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F = Gm₁m₂ / r²

F₂ = G × 2m₁ × 3m₂ / r²

F₂ = 6Gm₁m₂ / r²

But

F₁ = Gm₁m₂ / r²

Therefore

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F₂ = 6F₁

Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction

Learn more about gravitational force:

brainly.com/question/21500344

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6 0
2 years ago
Se aplica una fuerza neta de 25 N a una masa de 10 kg. ¿Cuál es la aceleración dada a la masa?
lys-0071 [83]

Answer:

Se queda

Explanation:

Porque 10 kg es más que 25N

4 0
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a moving ball rolls into a stationary ball. the total momentum of both balls after the collision will be
rosijanka [135]
The momentum of the rolling ball will have less momentum than before the collision and the stationary ball will have more momentum after the collusion.
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3 years ago
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