Answer:
The value of Ka 
It is a weak acid
Explanation:
From the question we are told that
The concentration of ![[HClO_2]=0.24M](https://tex.z-dn.net/?f=%5BHClO_2%5D%3D0.24M)
The concentration of ![[H^+]=0.051M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.051M)
The concentration of ![[ClO_2^-]=0.051M](https://tex.z-dn.net/?f=%5BClO_2%5E-%5D%3D0.051M)
Generally the equation for the ionic dissociation of 
is
The equilibrium constant is mathematically represented as
![= \frac{[H^+][ClO_2^-]}{[HClO_2]}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%5BH%5E%2B%5D%5BClO_2%5E-%5D%7D%7B%5BHClO_2%5D%7D)
Substituting values since all value of concentration are at equilibrium
Since the value of is less than 1 it show that in water it dose not completely
disassociated so it an acid that is weak
Answer:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
Explanation:
Chemical equation:
CO + O₂ → CO₂
Balanced chemical equation:
2CO + O₂ → 2CO₂
The standard enthalpy for the formation of CO = -110.5 kj/mol
The standard enthalpy for the formation of O₂ = 0 kj/mol
The standard enthalpy for the formation of CO₂ = -393.5 kj/mol
Now we will put the values in equation:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol + 0]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol]
ΔH0reaction = -283 kj/mol
Balanced chemical equation:
2 H2 + 1 O2 = 2 H2O
4 g H2 -------> 32 g O2 -----------> 36 g H2O
↓ ↓ ↓
14.0 g ---------> 2.0 g O2 ----------> mass H2O ?
32 * mass H2O = 2.0 * 36
32 * mass H2O = 72
mass of H2O = 72 / 32
mass of H2O = 2.25 g
hope this helps!.
Answer:
Nose
Explanation:
Because every time I touch it's nose, it will hide itself into the shell faster than other places
