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2 years ago

Based on its location on the periodic table, what group does Strontium belong to?

Chemistry

2 answers:

Gnom [1K]2 years ago

8 0

Answer:

alkaline earth metals

Explanation:

NeX [460]2 years ago

3 0

Answer:

Group 2

Explanation:

Strontium (Sr), chemical element, one of the alkaline-earth metals of Group 2 (IIa) of the periodic table.

Hope this helps

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When 2.50 grams of copper reacts with oxygen?

ycow [4]

Mass oxigen = 2.81 - 2.50 = 0.31 g
Moles O = 0.31 g / 15.9994 g/mol =0.0194

moles Cu = 2.50 g / 63.546 g/mol =0.0393

we divide by the smallest number
0.0194 / 0.0194 = 1 => O
0.0393 / 0.0194 = 2 => Cu
the formula is Cu2O ( Copper (I) oxide )
Ya got this

7 0

3 years ago

Using the information on page 508, describe a way to make a universal indicator that would tell you the ph of a solution between

vovikov84 [41]

pH stands for the power of hydrogen. pH that ranges form 1-6.9 are acid substances. At pH 1 - 2.9, the substance is highly acidic which will have the color from red to red - orange. At pH 3 - 4, the substance is mildly acidic and the color range is from red - orange to orange. At pH 4.1 – 6.9, the substance is weakly acidic and the color range is from orange to yellow. At pH 7, it is neutral and it is green in color. At pH 7.1-14, it is basic. At pH 7.1 - 10.9, the substance is weakly basic the color range is from green to blue. At pH 11 - 13, the substance is mildly basic and the color range is from blue to purple. At pH 13.1 – 14, the substance is highly basic and the color range is from purple to light purple.

8 0

3 years ago

What is the correct formula that would result from the combination of the two ionic species?

Soloha48 [4]

Answer:

CsCl

Explanation:

The ionic species are:

Cs⁺ and Cl⁻

6 0

2 years ago

Please help me like now please

777dan777 [17]

Answer:

1-1) NaHCO3 + CH3COOH --> NaCH3COO + H2O + CO2

1-2) 0.5 mole of CO2

2-1) 2C4H10 + 13O2 --> 8CO2 + 10H2O

2-2) 4 mol CO2

Explanation:

Question 1

NaHCO3 + CH3COOH --> NaCH3COO + H2O + CO2

To balance the equation, count the number of atoms on both sides of the equation

(1 Na, 1+3+1H, 1+1+1C, 3+2Oxygen) --> (1 Na, 1+1+1C, 3+2H, 2+1+2Oxygen)

Combining the pluses will give you the following

(1 Na, 5H, 3C, 5Oxygen) --> (1 Na, 3C, 5H, 5Oxygen)

Both sides are the same, therefore the chemical equation is balanced (originally).

From the equation, we can see that 1 mole of NaHCO3 produces 1 mole of CO2.

So that means 0.5 mole of NaHCO3 would produce 0.5 mole of CO2.

Question 2

C4H10 + O2 --> CO2 + H2O

Again, count the number of atoms on both sides of the equation

(4C, 10H, 2O) --> (1C, 2H, 3O) This time left does not equal right side

You now need to find factors that can make both sides equal.

C4H10 + O2 --> 4CO2 + H2O Now the C is balanced, let's recount 

(4C, 10H, 2Oxygen) --> (4C, 8+1Oxygen, 2H) H&O is still not balanced

C4H10 + O2 --> 4CO2 + 5H2O Now the H is balanced, let's recount

(4C, 10H, 2Oxygen) --> (4C, 8+5Oxygen, 10H) O is still not balanced

C4H10 + (13/2)O2 --> 4CO2 + 5H2O Now the O is balanced

(4C, 10H, 13Oxygen) --> (4C, 13Oxygen, 10H)

But because 13/2 is a fraction, we want to eliminate that by multiplying every reactant and product by 2 (the denominator).

2C4H10 + 13O2 --> 8CO2 + 10H2O Now it's completely balanced!

(8C, 20H, 28Oxygen) --> (8C, 28Oxygen, 20H) Yayy! It's balanced.

Now, 2 mol C4H10 produces 8 mol CO2.

So 1 mol C4H10 produces 4 mol CO2.

6 0

2 years ago

Electrons is an excited state are more likely to enter into chemical reactions.

Alex17521 [72]

A. True would be the best answer

3 0

3 years ago