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A jar contains 3 red, 2 white, and 1 green marble. Aside from color, the marbles are indistinguishable. Two marbles are drawn at

IRISSAK [1]

Answer:

0.6

Step-by-step explanation:

A permutation is an arrangement of outcomes whereas a combination is a grouping of outcomes.

Order matters in case of permutations but does not matter in combinations.

Given:

Number of red marbles = 3

Number of white marbles = 2

Number of green marbles = 1

To find: probability of picking 4 marbles and getting one of each color

Solution:

Total number of outcomes = $6_C__4$ = $\frac{6!}{4!\,2!}=\frac{6\times 5\times 4!}{4!\times 2}=15$

Number of favourable outcomes = 2 red, 1 white and 1 green marble + 1 red, 2 white and 1 green marble = $3_C_2\,2_C_1\,1_C_1+3_C_1\,2_C_2\,1_C_1$ = $\frac{3!}{2!\,1!}\times \frac{2!}{1!\,1!}\times 1+\frac{3!}{2!\,1!}\times 1\times 1=6+3=9$

So, probability of picking 4 marbles and getting one of each color = Number of favourable outcomes/Total number of outcomes = $\frac{9}{15}=\frac{3}{5}=0.6$

4 0

3 years ago

If x is equal to -6 which equality is true

Papessa [141]

Answer:

-5 - 3x > 10

Step-by-step explanation:

x = -6

Plug in the x value for each inequality:

-5 - 3(-6) > 10

-5 + 18 > 10

13 > 10

True

-3 - 5(-6) < -14

-3 + 30 < -14

27 < -14

False

1 - 2(-6) > 13

1 + 12 > 13

13 > 13

False

2 - (-6) < -3

2 + 6 < -3

8 < -3

False

Only one of these is true; that is the answer.

8 0

3 years ago

S=[E,F,G,H,J] identify the ways to select two members from s allowing the repetition

Fofino [41]

Answer: There are 25 ways to select two members.

Step-by-step explanation:

Since we have given that

S={E,F,G,H,J}

Number of elements = 5

We need to select two members from S allowing the repetition.

We will use "Fundamental theorem of counting":

There are 5 choices for the first member.

There are 5 choices for the second member.

So, Number of ways would be

$5\times 5\\\\=25$

Hence, there are 25 ways to select two members.

8 0

3 years ago

Which expressions are equivalent to -3(2+7) A: -6+21 or B:-21+6

Neporo4naja [7]

<u>Answer:</u>

None

<u>Explanation:</u>

-3(2+7) = -3×9 = -27

-6+21 = 15

-21+6 = -15

Hence there is no equivalence

3 0

3 years ago

Determine if the sides are greater than (>), less than (<), or equal (=) to each other.

DochEvi [55]

In ∆BCE

$\\ \sf\longmapsto$

Opposite side to <E=BC

Opposite side to <B=EC

<E=<B

$\\ \sf\longmapsto BC=EC$

4 0

3 years ago