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3 years ago

Explain how a hurricane poses a threat to life and the biosphere. Use complete sentences.

2 answers:

8 0

Answer: Hurricanes generate strong winds that can completely defoliate forest canopies and cause dramatic structural changes in wooded ecosystems. Animals can either be killed by hurricanes or impacted indirectly through changes in habitat and food availability caused by high winds, storm surge, and intense rainfall.

Explanation:

Snezhnost [94]3 years ago

4 0

Answer:

A hurricane can cause extreme damage to the biosphere and the geosphere. A hurricane can leave water standing therefore sinking itself into the geosphere. The biosphere can be permanently effected because it can kill, injure, and destroy the biosphere and what the biosphere creates (buildings, parks).

Explanation:

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How many moles are there in 987 grams of Ra(OH)2? id also love to know the simplest equation for converting moles --> so i co

OlgaM077 [116]

Mole = $\frac{mass}{molar mass}$

Mass of Radium Hydroxide = 987g
Molar Mass of $Ra(OH) _{2}$ = ((226) + (2 * 16) + (2 * 1))
= 260 g / mol

∴ Moles of <span> $Ra(OH) _{2}$ = </span> $\frac{987 g }{ 260 g / mol }$
= 3.796 mols

6 0

3 years ago

A certain substance melts at a temperature of . But if a sample of is prepared with of urea dissolved in it, the sample is found

pshichka [43]

Answer:

2.2 °C/m

Explanation:

It seems the question is incomplete. However, this problem has been found in a web search, with values as follow:

" A certain substance X melts at a temperature of -9.9 °C. But if a 350 g sample of X is prepared with 31.8 g of urea (CH₄N₂O) dissolved in it, the sample is found to have a melting point of -13.2°C instead. Calculate the molal freezing point depression constant of X. Round your answer to 2 significant digits. "

So we use the formula for <em>freezing point depression</em>:

ΔTf = Kf * m

In this case, ΔTf = 13.2 - 9.9 = 3.3°C

m is the molality (moles solute/kg solvent)

350 g X ⇒ 350/1000 = 0.35 kg X

31.8 g Urea ÷ 60 g/mol = 0.53 mol Urea

Molality = 0.53 / 0.35 = 1.51 m

So now we have all the required data to <u>solve for Kf</u>:

ΔTf = Kf * m

3.3 °C = Kf * 1.51 m

Kf = 2.2 °C/m

5 0

3 years ago

How many pounds of ice are required to absorb 4900 kJ of heat as the ice melts? The heat of fusion of water is 0.334 kJ/g.

Goshia [24]

Answer:

m = 32.34 pounds of ice.

Explanation:

In this case we need to use the following expression of heat:

q = m * ΔHf (1)

Where:

q: heat absorbed in J or kJ

m: mass of the compound in g

ΔHf: heat of fusion of the water in kJ/g

We are asked to look for the mass of ice in pounds, so after we get the grams, we need to convert the grams to pounds, using the following conversion:

1 pound --------> 453.59 g (2)

So, we have the heat and heat of fusion, from (1) let's solve for the mass, and then, using (2) the conversion to pounds:

q = m * ΔHf

m = q / ΔHf

m = 4900 / 0.334 = 14,670.66 g of ice

Now, the conversion to pounds:

m = 14,670.66 g * 1 pound/453.59 g

<h2>m = 32.34 pounds of ice.</h2>

Hope this helps

5 0

3 years ago

6. A quiet sound exerts a pressure of 4.00 x 10^-8 kPa (kPa= kilopascals, a pressure unit). What is this pressure measured in at

Radda [10]

Answer:

GOOGLE MY HUMAN

Explanation:

GOOGLE!!!!!

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3 years ago

In Cellulose, C6H7O2(OH)3

GarryVolchara [31]

GB do GB fo fi ch by GB hi hi every hdhs fi saw

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3 years ago