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lara31 [8.8K]
2 years ago
12

Acetaldehyde is a substance commonly used in chemical factories. It is often produced by

Chemistry
1 answer:
Eduardwww [97]2 years ago
5 0

There are 48 hydrogen atoms,  24 carbon atoms, and 12 oxygen atoms, also 12 molecules of acetaldehyde were produced in the reaction.

The equation of the reaction is;

12C2H4 + 6O2 ------> 12 CH3CHO

In order to approach this problem, the balanced reaction equation is the first step. There are 12 ethylene molecules and six oxygen molecules. These will combine as shown.

There number of atoms involved are as follows;

H = 48

C = 24

O = 12

There are 12 molecules of acetaldehyde produced in the reaction.

Learn more: brainly.com/question/9743981

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Choose a depiction of a gas sample containing equal molar amounts of xenon and argon as described by kinetic molecular theory. R
Setler79 [48]

Answer:

On the attached picture.

Explanation:

Hello,

At first, it is important to remember that kinetic molecular theory help us understand how the molecules of a gas behave in terms of motion. In such a way, the relative velocity of a gas molecule has the following relationship with the gas' molar mass:

V∝\frac{1}{\sqrt{M} }

That is, an inversely proportional relationship which allows us to infer that the bigger the molecule the slower it. In this manner, as argon is smaller than xenon, it will move faster.

Now, as the gases are in equal molar amounts and considering that argon moves faster, on the attached picture you will find the suitable depiction of the gas sample, since red dots (argon) have a larger tail than the blue dots (xenon).

Best regards.

7 0
3 years ago
Read 2 more answers
In an experiment, a student was assigned to find the formula of an unknown hydrate that weighed 15.67g. The anhydrate, XCO3 (mol
meriva

Answer:

5.0 moles of water per one mole of anhydrate

Explanation:

To solve this question we must find the moles of the anhydrate. The difference in mass between the dry and the anhydrate gives the mass of water. Thus, we can find the moles of water and the moles of water per mole of anhydrate:

<em>Moles Anhydrate:</em>

7.58g  * (1mol / 84.32g) = 0.0899 moles XCO3

<em>Moles water:</em>

15.67g - 7.58g = 8.09g * (1mol / 18.01g) = 0.449 moles H2O

Moles of water per mole of anhydrate:

0.449 moles H2O / 0.0899 moles XCO3 =

5.0 moles of water per one mole of anhydrate

6 0
2 years ago
A piece of iron is heated to 120'C then placed in a calorimeter containing 50g of water. The water temperature is raised from 30
Lana71 [14]

Answer:

Mass of iron = 59.375 gm

Explanation:

Calories ( or joules) are added to the water by the hot steel so at the endpoint they are BOTH at 40 C

 The water gains:

     4.18  j/g-C  * 50 * (40-30 C) = 2090 j

The steel gave up 2090 j going from 120 to 40 C

2090 = .44 j/g-C  * m * (120-40)    solve fro m = 59.375 gm

3 0
2 years ago
You are given the following three half-reactions:(1) Fe³⁺(aq) + e⁻ ⇄ Fe²⁺(aq) (2) Fe²⁺(aq) +2e⁻ ⇄ Fe(s) (3) Fe³⁺(aq) +3e⁻ ⇄ Fe(s
RideAnS [48]

The E°half-cell of the (3) is 0.33 volts .

Given,

(1)  Fe3+(aq) +e =Fe2+(aq)

(2) Fe2+(aq) +2e = Fe(s)

(3) Fe3+(aq) +3e = Fe(s)

We know ,

E° half-cell of (1) is 0.77 volts .

E° half cell of ( 2) is -0.44 volts .

By resolving or adding equation 1 and 2 we will get (3) ,

Thus , the value of the E° half cell of (3) is given by ,

E°cell = E° half-cell of (1 ) + E° half-cell of (2 ) = 0.77-0.44 = 0.33 volts

Hence the E° half-cell of ( 3 ) is 0.33 volts .

<h3>What is cell potential? </h3>

It is the difference between the electrode potentials of two half cells.

it also defined as the force which causes the flow of electrons from one electrode to the another and thus results in the flow of current.

Ecell = E( cathode) - E ( anode)

<h3>What is electrode potential ? </h3>

The tendency of the electrode to lose of gain electrons is called as electrode potential.

Learn more about cell potential here :

brainly.com/question/19036092

#SPJ4

4 0
1 year ago
Why can't helium bond with hydrogen?
Iteru [2.4K]
Hydrogen and Helium cannot bond together. Put aside the inertness of helium (or all noble gases), bond formation is only favored when the final state of the two elements is more stable than their initial state. ... Helium compounds has some predictions though none of them contain only those two elements.
8 0
3 years ago
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