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pochemuha
3 years ago
12

FIND THE SLOPE OF THE LINE... A) 1/2 B) 2 C) - 1/2 D) -2

Mathematics
1 answer:
Ainat [17]3 years ago
8 0

Answer:

The slope would be C) -1/2

Step-by-step explanation:

To find it, we need to use the slope formula and two points on the line. The points we'll use are (0, -3) and (2, -4)

m(slope) = (y2 - y1)/(x2 - x1)

m = (-3 - -4)/(0 - 2)

m = 1/-2

m = -1/2

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Help please with this math question
Vanyuwa [196]
To solve this question, simply use the formula to find the volume of the cylinder,

V = Pi r^2 • h

V = 3.14 • 4^2 • 4.

Then compare the value for volume to the closest number on the number line. Is it in between 2 numbers, exactly one number on the number line or very close to one number as in the number line.






8 0
3 years ago
Read 2 more answers
What is the answer for number 15 16 17
stira [4]
15.

6 pachages
each pcage has 30
6*30=180 total

17 left over
how many used
used=total-left over
used=180-17
used=163




16. xy is 2 digit number
multiplules of 10 (whole multipules) always end with 0 so y=0

and has 3 as one of its factors
factors of 3 is 3,6,9,12
30,60,90 is answer



17.
30 in 9 parks
30 times 9
30=10 times 3
3*10*9
group the 3 and 9
10*(3*9)
3*9=27
10*(27)
270






15. 163
16. 30,60,90
17. see above, 270
6 0
4 years ago
1. In the figure below ∡=153°, ∢=(5+5)°, and ∢=(3+12)°. Find the measure of ∢ and ∢. Show all work.
murzikaleks [220]

Answer: The answer is 10 and 15

7 0
3 years ago
Answer pls the question
blondinia [14]

Answer:

A AND D ARE CORRECT.

Step-by-step explanation:

IT IS A NUMBER LINE SO IT IS JUST BASIC ADDITION AND SUBTRACTION.

3 0
3 years ago
Read 2 more answers
Find the values of the six trigonometric functions of theta with the given constraint.
Evgesh-ka [11]

Answer:

The six trig ratios at 3pi/2 are:

sin(3pi/2)=-1

cos(3pi/2)=0

tan(3pi/2) (undefined)

csc(3pi/2)=-1

sec(3pi/2) (undefined)

cot(3pi/2)=0

Step-by-step explanation:

If tangent is undefined then cosine would have to be 0 given that tangent is the ratio of sine to cosine.

cosine is 0 at pi/2 and 3pi/2 in the first rotation of the unit circle.

3pi/2 satisfies the given constraint.

The six trig ratios are therefore:

sin(3pi/2)=-1

cos(3pi/2)=0

tan(3pi/2)=-1/0 (undefined)

Reciprocal values:

csc(3pi/2)=-1

sec(3pi/2) undefined since cos(3pi/2)=0

cot(3pi/2)=0/-1=0

4 0
3 years ago
Read 2 more answers
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