Answer:
Δw =7.95 kg/1000m^3
q = 62362.3 kg/1000m^3
Explanation:
To solve this problem we first need to use the psycrometric chart to determine the enthalpy h1, specific volume vi and absolute humidity col by using the given temperature T1 = 32°C and the relative humidity Ф1 = 95%.
h_1 = 106.5 kJ/kg
v_1 = 0.91 m^3/kg
w_1 = 0.02905
We will also need the enthalpy h2 and the absolute humidity w_2 at the exit point. We will again use the pyscrometric chart and the given temperature T_2 = 24°C. From the problem we also know that the exit relative humidity is = 60%.
h2 = 52.6 kJ/kg
w_2 = 0.01119
We need to express the final results in units per 1000 m^3. To do that we will need the mass m of this volume of air V and to calculate that we will use the given pressure p = 1 atm = 101.3 kPa.
m = R_a*T_1/V.p
m = 1000*101.3/0.287*305K
m = 1157 kg
Because it is a closed system, the amount of water removed Δw can be calculated as:
Δw =w_1 - w_2
Δw =0.02905- 0.01119
Δw =0.00687 kg/kg* 1157kg/1000m^3
Δw =7.95 kg/1000m^3
From the energy balance equation we can calculate the specific heat q removed from the air.
q = h_1 - h_2
q = 106.5 kJ/kg - 52.6 kJ/kg
q = 53.9 kJ/kg * 1157kg/1000m^3
q = 62362.3 kg/1000m^3
Answer:
option A. Inferring
Explanation:
inferring/ inference as reading strategy simply is the process by which one uses what he/she knows to make a guess about what you don't know or reading between the lines. Readers in making inferences uses clues found inside text along with their own views or experiences to help them figure out what is not directly said,thereby causing a personal and memorable text. for one to draw an inference from the passage via reading, Identify if its an Inference Question.inferring involves Trusting the Passage or what you are seeing, then you start Hunting for Clues thereafter you Narrow Down the Choices. and then come to a conclusion or Practice.
Answer:
Check the explanation
Explanation:
Determine the weight o ids in the each truck °slim the relation,
W,=
Here, W is net weight of soil and water on the truck and w is water content
substitute 72 7 kN for W and 15% for w.
you will need to also determine the number of truck loads required using the relation:
Number of truck loads required = 
Kindly check the attached image below for the full explanation to the question above.
Answer:
(a) Work done is 1.59642 kJ
(b) Useful power supplied = 0.1298 kW
Explanation:
(a) Work done = mass of crate × acceleration due to gravity × distance = 90.5 kg × 9.8 m/s^2 × 1.8 m = 1596.42 kgm^2/s^2 × 1 J/1 kgm^2/s^2 × 1 kJ/1000 J = 1.59642 kJ
(b) Useful power supplied = work done ÷ time = 1.59642 kJ ÷ 12.3 s = 0.1298 kJ/s × 1 kW/1 kJ/s = 0.1298 kW
Answer:
to plan, design, and oversee the construction of a building
