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3 years ago

Principals of Construction intro

Engineering

1 answer:

Nadusha1986 [10]3 years ago

8 0

Answer:

The answer is safety documents

Explanation:

Every company is responsible

For people documents

Is very important for every company

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The liquid-phase reaction:

OLEGan [10]

Answer:

attached below

Explanation:

4 0

3 years ago

Tech A says that a cylinder leakage test is performed on a cylinder with low compression to determine the severity of the leak a

Karolina [17]

Tech A djjdjdndnndndbdbx

4 0

3 years ago

A gas expands in a piston-cylinder assembly from p1 = 8 bar, V1 = 0.02 m3 to p2 = 2 bar. The relation between pressure and volum

Charra [1.4K]

Answer:

The heat transfer is 29.75 kJ

Explanation:

The process is a polytropic expansion process

General polytropic expansion process is given by PV^n = constant

Comparing PV^n = constant with PV^1.2 = constant

n = 1.2

(V2/V1)^n = P1/P2

(V2/0.02)^1.2 = 8/2

V2/0.02 = 4^(1/1.2)

V2 = 0.02 × 3.2 = 0.064 m^3

W = (P2V2 - P1V1)/1-n

P1 = 8 bar = 8×100 = 800 kPa

P2 = 2 bar = 2×100 = 200 kPa

V1 = 0.02 m^3

V2 = 0.064 m^3

1 - n = 1 - 1.2 = -0.2

W = (200×0.064 - 800×0.02)/-0.2 = -3.2/-0.2 = 16 kJ

∆U = 55 kJ/kg × 0.25 kg = 13.75 kJ

Heat transfer (Q) = ∆U + W = 13.75 + 16 = 29.75 kJ

7 0

3 years ago

A 10-mm-diameter Brinell hardness indenter produced an indentation 1.55 mm in diameter in a steel alloy when a load of 500 kg wa

BigorU [14]

Answer:

HB = 3.22

Explanation:

The formula to calculate the Brinell Hardness is given as follows:

$HB = \frac{2P}{\pi D\sqrt{D^{2}- d^{2} } }$

where,

HB = Brinell Hardness = ?

P = Applied Load in kg = 500 kg

D = Diameter of Indenter in mm = 10 mm

d = Diameter of the indentation in mm = 1.55 mm

Therefore, using these values, we get:

$HB = \frac{(2)(500)}{\pi (10)\sqrt{10^{2}- 1.55^{2} } }$

HB = 3.22

4 0

3 years ago

How to find magnitude of net electric charge when current flows through a capacitor with initial charge?

Ksenya-84 [330]

Answer:

Q=q $e^{-t/RC}$

also

q=it

Explanation:

How to find magnitude of net electric charge when current flows through a capacitor with initial charge?

A capacitor is a device used in storing electric charges. The unit of capacitance is measured in farad

To find the magnitude of net electric charge in a capacitor, we use the following relation

Q=q $e^{-t/RC}$

Q=the magnitude of net electric charge in coulombs

t=the time for an electron tpo pass through the capacitor

R=the resistance of the capacitor , measured in ohms

C=the capacitance of the capacitor measures in Farad

q=initial quantity of charge

Having all the parameters above will make it possible to determine the net electric charge

Recall also that

q=it

quantity (coulombs)=current*time(s)

3 0

3 years ago