7. The charged object can have two polarities, positive or negative which is determined by the configuration of electron orbitals of the material. If there are free orbitals, it will likely gain electrons and produce a negative charge. If there are free electrons on the outermost orbitals, these electrons will be lost and the material will have a positive charge.
8. R<span>ubbing styrene and rabbit fur because rabbit fur has free orbitals which can hold electrons making styrene positive.
9. When it is dry and windy.
10. When there no other materials that can take or add electrons from or to it.
11. Static charge is dissipated through static electricity.
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Answer:
Explanation:
Ohm's law is define by the formula
V = IR where I is current in A, R is resistance in ohms
to calculate the resistance we use the formula above
I = 185 mA / 1000 = 0.185 A
case 1, R = V / I = 12 V / 0.185 A = 64.86 ohms
case 2, R = V / I = 90 / 1.25 A = 72 ohms
a) the resistor is not ohmic since there is no linear relationship between R and V ( as voltage increases, resistance ought to also increase)
b) rate of Joule heating in the case 1, P, power = IV = 0.185 A × 12 = 2.22 W
case 2, P = IV = 1.25 A × 90 V = 112.5 W
Reactivity is the tendency of a substance to undergo chemical reaction, either by itself or with other materials, and to release energy.
Answer:
a) 
b) the motorcycle travels 155 m
Explanation:
Let 
, then consider the equation of motion for the motorcycle (accelerated) and for the car (non accelerated):
where:
is the speed of the motorcycle at time 2
is the velocity of the car (constant)
is the velocity of the car and the motorcycle at time 1
d is the distance between the car and the motorcycle at time 1
x is the distance traveled by the car between time 1 and time 2
Solving the system of equations:
![\left[\begin{array}{cc}car&motorcycle\\x=v_0\Delta{t}&x+d=(\frac{v_0+v_{m2}}{2}}) \Delta{t}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dcar%26motorcycle%5C%5Cx%3Dv_0%5CDelta%7Bt%7D%26x%2Bd%3D%28%5Cfrac%7Bv_0%2Bv_%7Bm2%7D%7D%7B2%7D%7D%29%20%5CDelta%7Bt%7D%5Cend%7Barray%7D%5Cright%5D)
For the second part, we need to calculate x+d, so you can use the equation of the car to calculate x:
If the potential energy of the three-object system is to be a maximum (closest to zero), should object 3 be placed closer to object 1, closer to object 2, or halfway between them?
If the potential energy of the three-object system is to be a maximum (closest to zero), should object 3 be placed closer to object 1, closer to object 2, or halfway between them?
Object 3 should be placed closer to object 1.
Object 3 should be placed on a halfway between object 2 and object 1.
Object 3 should be placed closer to object 2.
Solution
I think that Object 3 should be placed closer to object 2.
