Since HCl04 is a strong acid, being [H+], and a molarity of 2.1 M.
To solve for pH:
pH = -log (M) = -log(2.1M) = -0.32, which is clearly a negative number.
However, to verify the answer, just use the pH meter in determining the pH of the solution.
(18000 L/hr) x (3 hr) x ( 0.965 kg/L) = 52110 kg
will be largest for 
.
Explanation: Ionization energy is the energy to knock off an electron from a gaseous atom of ion. First ionization energy or is the energy required to remove 1 loosely held electron from 1 mole of gaseous atoms to produce 1 mole of gaseous ion carrying (+)1 charge.
The electrons are filled according to Aufbau's rule and the orbitals which are strongly held to the nucleus follows the order 
.
Electron is released from the outermost shell that is from the electrons which are loosely held to the nucleus, this follows the pattern 
.
In configurations, 
The loosely held orbital is 4s, therefore electron will be lost from that easily.
Now, in 3p orbital, one configuration has 5 electrons and one has 1 electron.
The configuration having 5 electrons will be more tightly held by the nucleus because it has more electrons that the one having only 1 electron. Hence, the electron will be lost easily from the configuration having 
as the valence shell.
Therefore, the configuration will the largest .
Answer:
The various sources of such errors are given below.
Explanation:
- Sources of uncertainty or error could include necessary splattering of water leading to reduced cold water density as well as elevated temperatures of equilibration.
- The temperature might not have been reasonably stable when developers evaluated at every phase of the investigation or research.
So that the percentage of someone specific produces heat exploratory value systems inaccuracies can be somewhat massive.
The amount of Mg(OH)2 present after the reaction is complete is 0.136 moles of Mg(OH)2.
The equation of the reaction is;
2HNO3(aq) + Mg(OH)2(aq) -------> Mg(NO3)2(aq) + 2H2O(l)
Number of moles of Mg(OH)2 = 8.00 g/58 g/mol = 0.138 moles
Number of moles of HNO3 = 0.205 M × 24.2 mL/1000 = 0.00496 moles
Given that;
2 moles of HNO3 reacts with 1 mole of Mg(OH)2
0.00496 moles of HNO3 reacts with 0.00496 moles × 1 mole /2 moles = 0.00248 moles of Mg(OH)2
Hence, Mg(OH)2 is the reactant in excess.
The amount of Mg(OH)2 remaining = Amount present - Amount reacted
Hence; 0.138 moles - 0.00248 moles = 0.136 moles of Mg(OH)2
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