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Dominik [7]
3 years ago
15

Calcium drawing look like

Chemistry
1 answer:
leva [86]3 years ago
7 0
Not the best drawing but hope thats correct

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If the caffeine concentration in a particular brand of soda is 2.85 mg/oz, drinking how many cans of soda would be lethal? Assum
alina1380 [7]

Answer:

2,375 cans

Explanation:

The strategy here is to use the information given to calculate the lethal dosage contained in the number of cans we will compute.

We know the lethal dosage is

Ld = 10.0 g caffeine

and we also know that the oncentration of caffeine is:

2.85 mg/ oz

So our problem simplifies to calculate how many oz will contain the lethal dose, and then given the ounces per can determine how many cans are required.

First convert the lethal dose in grams to mg:

Ld =( 10 g x 1000 mg ) = 10,000 mg caffeine

10,000 mg x ( 1 Oz / 2.85 mg ) = 28,500 oz

28500 oz x ( 1 can/12 oz ) = 2,375 cans

We could also have calculated it in one step  using conversion factors:

Number of cans = 10000 mg x 1 oz/ 2.85 mg x 1 can / oz = 2,375 cans

7 0
3 years ago
What does one mole of H2O correspond to?
Andrei [34K]

Answer: A

Explanation:

8 0
3 years ago
Read 2 more answers
[2]
vitfil [10]

Explanation:

The temperature of the molten iron remained constant at 2750°C because of the heat absorbed to effect the phase change and not to change the temperature.

The heat of vaporization is a latent or hidden heat absorbed by substances that causes a phase change from liquid to gas.

  • In essence, the heat is used to break intermolecular bonds between the particles of the melted vat.
  • If enough heat is no supplied the molten vat will not boil off and become vapor.
  • In transitioning from liquid to gas, heat is absorbed by a body to effect the phase change.
  • When the body acquires enough heat, the particles are able to break off and boil.
  • At the 2750°C  mark, this is what is happening.

learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

6 0
3 years ago
If liquid carbon disulfide reacts with 450 mL of oxygen to produce the gases carbon dioxide and sulfur dioxide, what volume of e
ivolga24 [154]

If excess carbon disulfide reacts with 450 mL of oxygen, 150 mL of carbon dioxide and 300 mL of sulfur dioxide gases would be produced respectively.

<h3>Stoichiometric calculation</h3>

The reaction between liquid carbon disulfide and oxygen is represented by the equations below:

CS_2 + 3O_2 -- > CO_2 + 2SO_2

The mole ratio of oxygen to carbon dioxide and sulfur dioxide produced is 3:1:2.

Thus, for 450 mL oxygen, 1/3 x 450 = 150 mL of carbon dioxide will be required.

Also for 450 mL of oxygen, 2/3 x 450 = 300 mL of sulfur dioxide will be required.

More on stoichiometric calculations can be found here: brainly.com/question/27287858

#SPJ1

5 0
2 years ago
Zinc + Hydrochloric acid — Zinc chloride + Hydrogen [Zn +2 HCI → ZnCl2 + H2] is an
Jet001 [13]
Double replacement i believe
6 0
3 years ago
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