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jenyasd209 [6]
3 years ago
12

How can mass and energy behave in an open system

Chemistry
1 answer:
algol133 years ago
3 0
An open system<span> is a system that has external interactions.</span>
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Which of the following is a way to increase the solubility of a solid in water? Select all that apply.(PLEASE HELP ME! THIS IS T
Thepotemich [5.8K]

Answer:

C and D

Explanation:

8 0
3 years ago
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A plate of the steel hull of a ship develops a large crack when the ship strikes a reef. Analysis of the steel’s composition sho
motikmotik
Probably Sulfur, low mp and hardness compared to the other metals
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V2O5 + Ca = V + CaO balance the eqaution
andreyandreev [35.5K]

Answer: The balanced equation is V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO.

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, V_{2}O_{5} + Ca \rightarrow V + CaO

Here, number of atoms on reactant side are as follows.

  • V = 2
  • O = 5
  • Ca = 1

The number of atoms on product side are as follows.

  • V = 1
  • O = 1
  • Ca = 1

In order to balance this equation, multiply Ca by 5 on reactant side. Multiply V by 2 and CaO by 5 on product side. Therefore, the equation can be rewritten as follows.

V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO

Now here, number of atoms on reactant side are as follows.

  • V = 2
  • O = 5
  • Ca = 5

The number of atoms on product side are as follows.

  • V = 2
  • O = 5
  • Ca = 5

Since, there are same number of atoms on both reactant and product side. So, the equation is now balanced.

Thus, we can conclude that the balanced equation is V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO.

5 0
3 years ago
Which group of elements reacts violent with elements from Group 1
castortr0y [4]
The halogen react aggressively with the alkali metals in group 1
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4 years ago
THIS iS A Ratio Problem
Arte-miy333 [17]

Answer:

30 moles of CO₂

Explanation:

balanced equation ,

CS₂+3O₂ → CO₂+2SO₂

From equation, 3 moles of O₂ are needed to make 1 mol of CO₂.

This means to produce 1 mol of CO₂, we need 3 moles of O₂, then how many moles of CO₂ will be produced from 90 moles of O₂ ?

Use unitary method to solve such problems,

Number of moles of CO₂ that will be produced:

= \frac{90 \times 1}{3}

=\frac{90}{3}

= 30 moles of CO₂

4 0
4 years ago
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