Answer:
Zn3P2O8
Explanation:
In this particular question, it is necessary to convert the respective masses to percentages. We convert to percentages by placing each mass over the total mass and multiplying by 100%. Since the total is 50mg, conversion to percentage can be done by multiplying the masses by 2 as 100/50 is 2
For Oxygen = 16.58 * 2 = 33.16%
For phosphorus = 8.02 * 2 = 16.04%
For zinc = 25.40 * 2 = 50.80%
We then proceed to divide these percentages by their respective atomic masses. The atomic mass of oxygen, phosphorus and zinc are 16, 31 and 65 respectively.
O = 33.16/16 = 2.0725
P = 16.04/31 = 0.5174
Zn = 50.80/65 = 0.7815
Now, we divide by the smallest value which is that of the phosphorus
O = 2.0725/0.5174 = 4
P = 0.5174/0.5174 = 1
Zn= 0.7815/0.5174 = 1.5
Now, we need to multiply through by 2. This yields: O = 8, P = 2 and Zn = 3
The empirical formula is thus: Zn3P2O8
125 Kelvin turns into -146 C
Hey!
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Steps To Solve:
~Substitute
3(2) - 2(3)
~Subtract
6 - 6
~Simplify
0
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Answer:
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Hope This Helped! Good Luck!
Answer:
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Explanation:
Hello there!
In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:

Regards!