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Gekata [30.6K]
3 years ago
10

the pressure on a 205 mL volume of gas is decreased from 985 mm hg to 615 mm hg while constant temperature is maintained, What i

s the new volume of the gas?
Chemistry
2 answers:
Softa [21]3 years ago
7 0
The new volume of gas should be 328.33 mL
viktelen [127]3 years ago
4 0

Answer:

\boxed {\boxed {\sf 328 \ mL}}

Explanation:

The pressure on the gas changes, while the temperature remains constant, and we want to find the new volume. So, we will use Boyle's Law, which states there is an inverse relationship between the pressure on a gas and the volume of the gas. The formula is:

{P_1V_1}= P_2V_2

The pressure of the gas is originally 985 mm Hg and the volume is 205 milliliters.

985 \ mm \ Hg * 205 \ mL = P_2V_2

The pressure is decreased to 615 mm Hg, but the new volume is unknown.

985 \ mm \ Hg * 205 \ mL = 615 \ mm \ Hg * V_2

We are solving for the new volume, so we must isolate the variable V₂. It is being multiplied by 615 millimeters of mercury.. The inverse of multiplication is division, so we divide both sides of the equation by 615 mm Hg.

\frac {985 \ mm \ Hg * 205 \ mL}{615 \ mm \ Hg} = \frac{615 \ mm \ Hg * V_2}{615 \ mm \ Hg}

\frac {985 \ mm \ Hg * 205 \ mL}{615 \ mm \ Hg} = V_2

The units of millimeters of mercury (mm Hg) cancel.

\frac {985 \  * 205 \ mL}{615 } = V_2

\frac{201925 }{ 615} \ mL = V_2

328.3333333 \ mL = V_2

The original measurements have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.

The 3 to the right in the tenths place tells us to leave the 8 in the ones place.

328 \ mL \approx V_2

The new volume of the gas is approximately <u>328 milliliters.</u>

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vlabodo [156]

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Which of the following is the best example of kinetic energy being transformed into potential energy?
galben [10]

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The correct answer is A

Explanation:

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3 years ago
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LenaWriter [7]

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4 0
3 years ago
Fill in the missing data point. Show all calculations leading to an answer.
Aleksandr-060686 [28]

Answer:  

1090 mmHg  

Explanation:  

We know that with gases we must use a Kelvin temperatures, so let’s try a plot of pressure against the Kelvin temperature.  

We can create a table as follows  

<u>t/°C</u>  <u>T/K</u>  <u>p/mmHg</u>  

  10   283      726  

  20  293      750  

  40   313      800  

  70  343      880  

100  373       960  

150  423        ???  

I plotted the data and got the graph in the figure below.  

It appears that pressure is a linear function of the Kelvin temperature.  

y = mx + b  

where x is the slope and b is the y-intercept.

===============

<em>Calculate the slope  </em>

I will use the points (275, 700) and (380, 975).  

Slope = Δy/Δx = (y₂ - y₁)/(x₂ -x₁) = (975 -700)/(380 – 275) = 275/105 = 2.619  

So,  

y = 2.619x + b  

===============

<em>Calculate the intercept </em>

When x = 275, y = 700.  

700 = 2.619 × 275 + b  

700 = 720 + b     Subtract 720 from each side and transpose.  

b = -20  

So, the equation of the graph is  

y = 2.619x -20  

===============

<em>Calculate the pressure</em> at 423 K (150°C)  

y = 2.619 × 423 - 20  

y = 1110 - 20  

y = 1090

At 150 °C, the pressure 1090 mmHg.  

The point is approximately at the position of the black dot in the graph.  

7 0
3 years ago
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