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2 years ago

What carries the useful energy of a lamp to its surroundings?

1 answer:

6 0

A. The potential energy from the batteries in the torch is transferred to the filament of the bulb. The energy is transferred to the surroundings as thermal energy and light. Most of the energy is transferred as thermal energy which is not useful and only some of the energy is transferred as light

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What is the driving force for the reaction of HCl(aq) and NaOH(aq)?

Andru [333]

HCl and NaOH react based on the following equation:
HCl + NaOH ..............> NaCl + H2O

This reaction is known as a double replacement reaction. In this types of reactions, the electrolyte (and the solvent) is water and the driving force is mainly the formation of a non-electrolyte produce.

Based on this, the driving force in the above neutralization reaction is the formation if the non-electrolyte salt (NaCl)

8 0

2 years ago

Monobromination of toluene gives a mixture of three bromotoluene products. Draw and name them.

Art [367]

Answer:

o-bromotoluene, m-bromotoluene and p-bromotoluene.

Explanation:

Hello,

In this case, on the attached picture you will find the reaction which yields o-bromotoluene as the first product, m-bromotoluene as the second product and p-bromotoluene as the last one since the substitution could be done at the second (ortho), third (meta) or fourth (para) carbons on the toluene.

Regards.

5 0

3 years ago

What is the solubility of argon (in units of grams per liter) in water at 25 °C, when the Ar gas over the solution has a partial

beks73 [17]

Answer:

0.02405 g/L is the solubility of argon in water at 25 °C.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{Ar}=K_H\times p_{gas}$

where,

$K_H$ = Henry's constant = $1.40\times 10^{-3}mol/L.atm$

$p_{Ar}$ = partial pressure of carbonated drink = 0.51atm

Putting values in above equation, we get:

$C_{Ar}=1.40\times 10^{-3}mol/L.atm\times 0.430 atm\\\\C_{Ar}=6.02\times 10^{-4}mol/L$

Molar mass of argon = 39.95 g/mol

Solubility of the argon gas :

$6.02\times 10^{-4}mol/L\times 39.95 g/mol=0.02405 g/L$

0.02405 g/L is the solubility of argon in water at 25 °C.

5 0

3 years ago

Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.6 g of methane is

lianna [129]

Answer:

21.6 g

Explanation:

The reaction that takes place is:

CH₄ + 2O₂ → CO₂ + 2H₂O

First we convert the given masses of both reactants into moles, using their respective molar masses:

9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄

64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂

0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.

Now we calculate how many moles of water are produced, using the number of moles of the limiting reactant:

0.6 mol CH₄ * $\frac{2molH_2O}{1molCH_4}$ = 1.2 mol H₂O

Finally we convert 1.2 moles of water into grams, using its molar mass:

1.2 mol * 18 g/mol = 21.6 g

4 0

2 years ago

The reaction of 5.40 g of carbon with excess O2 yields 13.6 g of CO2. What is the percent yield of this reaction?

vazorg [7]

C + O2= CO2
$n = \frac{m}{mw}$
$n = \frac{5.4}{12} \\ n = 0.45 \: mol \: of \: carbon$
$n = \frac{13.6}{12 + 16 \times 2} \\ n = \frac{13.6}{44} \\ n = 0.31 \: mol \: of \: carbon \: dioxide$
CO2 is limit
5.4-3.72= 1.68 g of C is excess
5.4 g = 100%
3.72 g = x
x=68.9 %

4 0

2 years ago