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Fed [463]
3 years ago
8

What subtomic particles are found in the nucleus of an atom?​

Chemistry
2 answers:
DENIUS [597]3 years ago
8 0

Answer:

The nucleus contains two types of subatomic particles, protons and neutrons. The protons have a positive electrical charge and the neutrons have no electrical charge.

Explanation:

Arte-miy333 [17]3 years ago
4 0

Answer:

Protons and Neutrons are found in the nucleus while Electrons are found around the nucleus.

Hope this helps ^^

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List the four quantum numbers
Andreas93 [3]

Answer: In atoms, there are a total of four quantum numbers: the principal quantum number (n), the orbital angular momentum quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms).

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3 years ago
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The oxidation number of what atom or ion decreases in the following reaction?
Flauer [41]

The oxidation number of I (iodine) decreases the in the described chemical reaction from 0 to -1.

Explanation:

We have the following chemical reaction:

I₂ + 2 KCl → KI + Cl₂

The following atoms have a change in the oxidation number:

I with a 0 oxidation number (in I₂) goes to I with -1 oxidation number (in KI) by receiving 1 electron.

Cl with a -1 oxidation number (in KCl) goes to I with 0 oxidation number (in Cl₂) by losing 1 electron.

Learn more about:

oxidation number

brainly.com/question/6710925

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3 years ago
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3 years ago
What is the oxidation state magnesium?
erastova [34]
Magnesium is a 2+ metal, located in the alkaline earth metals group of the periodic table (group 2).
8 0
3 years ago
If 2.0 ml of 6.0m hcl is used to make a 500.0-ml aqueous solution, what is the molarity of the dilute solution?
svp [43]
Make sure that you understand what they are asking you from this question, as it can be confusing, but the solution is quite simple. They are stating that they want you to calculate the final concentration of 6.0M HCl once a dilution has been made from 2.0 mL to 500.0 mL. They have given us three values, the initial concentration, initial volume and the final volume. So, we are able to employ the following equation:

C1V1 = C2V2
(6.0M)(2.0mL) = C2(500.0mL)
Therefore, the final concentration, C2 = 0.024M.
4 0
3 years ago
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