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3 years ago

How many moles are in 260g of Al2(SO3)3 x 4H20

Chemistry

1 answer:

Basile [38]3 years ago

4 0

M=260 g
M=414.215 g/mol

n=m/M

n=260 g / 414.215 g/mol = 0.6277 mol

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Answer:

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Explanation:

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Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

$P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]$

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Solving for n=4:

$P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})$

$P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})$

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I hope it helps you!

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