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levacccp [35]
3 years ago
11

BRAINLYIST!! NEED HELP QUICK! DO BOTH! THANKS! BRAINLIEST!!

Physics
2 answers:
Thepotemich [5.8K]3 years ago
7 0

Answer:

first answer is Both....

second answer is path B

make me btain list

ZanzabumX [31]3 years ago
6 0
First answer is both second answer is B
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You ordered a large block of wood with length 5, width 2, and height 1 (each in feet). Unfortunately, the manufacturer can only
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If each side is 0.1 feet extra,
The volume will be 5.1*2.1*1.1= about 11.781.
Perhaps this helps.
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3 years ago
Which of the following usually occurs with a short circuit? a. All parts of the circuit will begin to carry higher amounts of cu
fgiga [73]

Answer:

Hi,

The correct answer option is; D. Most of the current will flow through one part of the circuit.

Explanation:

A short circuit is a low resistance path in an electric connection between two conductors supplying current in a circuit.

It happens when excess amounts of current flow in the power source through a 'short path'.

Short circuits occur at very high temperatures which is of course caused by the heat produced during dissipation.

An example of application of short circuit is arc welding, where heating is achieved through short circuit.

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3 years ago
What determines magnetism?
adelina 88 [10]
The magnetic form of a substance can be determined<span> by examining its electron configuration: if it shows unpaired electrons, then the substance is paramagnetic; if all electrons are paired, the substance is diamagnetic.</span>
6 0
4 years ago
After your school's team wins the regional championship, students go to the dorm roof and start setting off fireworks rockets. T
oksian1 [2.3K]

Answer:

required distance is 233.35 m

Explanation:

Given the data in the question;

Sound intensity I = 1.62 × 10⁻⁶ W/m²

distance r = 165 m

at what distance from the explosion is the sound intensity half this value?

we know that;

Sound intensity I is proportional to 1/(distance)²

i.e

I ∝ 1/r²

Now, let r² be the distance where sound intensity is half, i.e I₂ = I₁/2

Hence,

I₂/I₁ = r₁²/r₂²

1/2 = (165)²/ r₂²

r₂² = 2 × (165)²

r₂² = 2 × 27225

r₂² = 54450

r₂ = √54450

r₂ = 233.35 m

Therefore, required distance is 233.35 m

6 0
3 years ago
Strength of electromagnets
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Lines of Force around an Electromagnet. ... The magnetic field strength of an electromagnet is therefore determined by the ampere turns of the coil with the more turns of wire in the coil the greater will be the strength of the magnetic field.

6 0
3 years ago
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