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Drupady [299]
4 years ago
12

A cylindrical well is 15 meters deep and has a diameter of 1.6 meters. Approximately how many cubic meters of soil were dug out

to make the well?
(Use π = 3.14.)

A. 30.14 cubic meters
B. 37.68 cubic meters
C.120.57 cubic meters
D. 188.40 cubic meters

Mathematics
1 answer:
Elza [17]4 years ago
6 0
I hope this helps you

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The Falcone family is planning to drive from Syracuse, New York to Buffalo, New York. On a map with a scale of
Ad libitum [116K]

Answer:

The Falcones have to travel at 25 m/h to make the trip in 2 hours.

Step-by-step explanation:

In order to find the answer you have to use the formula to calculate speed:

speed=distance/time

distance=50 miles. The stament indicates that the distance between Syracuse and Buffalo is 1 inch and that the map has a scale of inch = 50 miles.

time=2 hours

Now, you can replace the values on the formula:

speed=50 miles/2 hours

speed=25 m/h

According to this, the answer is that the Falcones have to travel at 25 m/h to make the trip in 2 hours.

7 0
3 years ago
Two angles of a quadrilateral measure 200° and 50°. The other two angles are in a ratio of 2:9. What are the measures of those t
avanturin [10]

Answer:

20° and  90°

Step-by-step explanation:

Let 2x = measure of 1st angle

then 9x =  measure of 2nd angle

The sum of the measures of the angles of a quad is 360

200 + 50 + 2x + 9x = 360

250 + 11x = 360

11x = 110

x = 10

2x = 20°

9x = 90°

7 0
3 years ago
Am i correct? calculus
Advocard [28]
Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
\\\\\\
\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
\\\\\\
\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
-------------------------------\\\\


\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
-------------------------------\\\\
\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
\\\\\\
\cfrac{d\theta }{dt}=\cfrac{11}{75}

8 0
3 years ago
11.4÷35.7 answer estimated<br>(15 points)(brainliest included)<br>(incorrect answer=report)​
Gre4nikov [31]

Answer:

0.31932773109

Step-by-step explanation:

  • Set it up
  • Move the decimal point one place to the right for both of them
  • Then, do the long division
  • Keep adding zeros at the end until you have your answer
  • You can round it to 0.32 if you want
8 0
3 years ago
Can anyone show me the steps in order solve this problem
STatiana [176]
M∠A = 42°   [isosceles triangle]

m∠B = 180 - 42 - 42 = 96°  [in a triangle, the three interior angles always add to 180°]

m∠C = 180 - 96 - (x+12)
m∠C = 84 - x - 12
m∠C = 72 - x

2x+9 + 3x-1 + 72-x = 180
4x + 80 = 180
4x = 180 - 80
4x = 100
x = 100/4
x = 25

m∠C = 72 - x = 72 - 25 = 47°

<span>I hope this helped</span>

8 0
3 years ago
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