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Lisa [10]
3 years ago
15

A torsion balance has a sensitivity requirement (SR) of 4.5 mg. What is the MWQ of this balance if the maximum error permitted i

n using it is 3.6%?
Chemistry
1 answer:
dybincka [34]3 years ago
7 0

Explanation:

MWQ means the minimum weighable quantity.

Mathematically,         MWQ = \frac{Sensitivity}{1 - \text{fraction of accuracy}}

or,        MWQ = \frac{sensitivity}{\text{fractional error}}

It is given that sensitivity is 4.5 mg and maximum permitted error is 3.6%.

Therefore, fraction error = \frac{3.6}{100} = 0.036

Hence, we will calculate MWQ as follows.

                  MWQ = \frac{sensitivity}{\text{fractional error}}

                            = \frac{4.5 mg}{0.036}

                            = 125 mg

Thus, we can conclude that the MWQ of the given balance is 125 mg.

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The temperature of a sample of water changes from 10°C to 20°C when the water absorbs 100 calories of heat. What is the mass of
Vlad1618 [11]

Answer:

10 g

Explanation:

Right from the start, just by inspecting the values given, you can say that the answer will be  

10 g

.

Now, here's what that is the case.

As you know, a substance's specific heat tells you how much heat is needed to increase the temperature of  

1 g

of that substance by  

1

∘

C

.

Water has a specific heat of approximately  

4.18

J

g

∘

C

. This tells you that in order to increase the temperature of  

1 g

of water by  

1

∘

C

, you need to provide  

4.18 J

of heat.

Now, how much heat would be required to increase the temperature of  

1 g

of water by  

10

∘

C

?

Well, you'd need  

4.18 J

to increase it by  

1

∘

C

, another  

4.18 J

to increase it by another  

1

∘

C

, and so on. This means that you'd need

4.18 J

×

10

=

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

.

Now look at the value given to you. If you need  

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

, what mass of water would require  

10

times as much heat to increase its temperature by  

10

∘

C

?

1 g

×

10

=

10 g

And that's your answer.

Mathematically, you can calculate this by using the equation

q

=

m

⋅

c

⋅

Δ

T

 

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

Plug in your values to get

418

J

=

m

⋅

4.18

J

g

∘

C

⋅

(

20

−

10

)

∘

C

m

=

418

4.18

⋅

10

=

10 g

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3 years ago
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