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Lisa [10]
3 years ago
15

A torsion balance has a sensitivity requirement (SR) of 4.5 mg. What is the MWQ of this balance if the maximum error permitted i

n using it is 3.6%?
Chemistry
1 answer:
dybincka [34]3 years ago
7 0

Explanation:

MWQ means the minimum weighable quantity.

Mathematically,         MWQ = \frac{Sensitivity}{1 - \text{fraction of accuracy}}

or,        MWQ = \frac{sensitivity}{\text{fractional error}}

It is given that sensitivity is 4.5 mg and maximum permitted error is 3.6%.

Therefore, fraction error = \frac{3.6}{100} = 0.036

Hence, we will calculate MWQ as follows.

                  MWQ = \frac{sensitivity}{\text{fractional error}}

                            = \frac{4.5 mg}{0.036}

                            = 125 mg

Thus, we can conclude that the MWQ of the given balance is 125 mg.

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I think these are the answers:

Explanation:

created/rearranged

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A boy swings a rubber ball attached to a string over his head in a horizontal, circular path. The piece of string is 1.15 m long
gregori [183]

Answer:

v = 16.49 m/s

Explanation:

Given that,

Length of the string, l = 1.15 m

The ball makes 137 complete turns each minute.

We know that, 1 turn = 6.28 rad

137 turns = 860.79 rad

1 min = 60 s

\omega=\dfrac{860.79\ rad}{60\ s}\\\\=14.34\ rad/s

We need to find the tangential velocity of the ball. It can be given by

v=r\omega\\\\=1.15\times 14.34\\\\v=16.49\ m/s

So, the tangential velocity of the ball is 16.49 m/s.

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What is the total distance covered if you walk 5 meters to the north 5 meter east 5 meters south
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8 0
3 years ago
If 125 ml of o2 gas exerts a pressure of 1.0 atm inside a cylinder, what will the pressure be if the cylinder compressed the vol
Lelu [443]
<h2>Hello!</h2>

The answer is: The new pressure is 1.67 atm.

<h2>Why?</h2>

From the statement, we know that the temperature remains constant and the gas volume is changing, meaning that the new pressure will be different than the first pressure.

Since the temperature remains constant, we can calculate the new pressure using the Boyle's Law.

The Boyle's Law states that:

P_{1}V_{1}=P_{2}V_{2}

Where,  

P is the pressure of the gas.

V is the volume of the gas.

Then, the given information is:

V_{1}=125ml=0.125L\\P_{1}=1atm\\V_{2}=75ml=0.075L

Remember, 1 L is equal to 1000 mL.

So,

125mL*\frac{1L}{1000mL}=\frac{125mL*1L}{1000mL}=0.125L\\\\75mL*\frac{1L}{1000mL}=\frac{75mL*1L}{1000mL}=0.075L

So, calculating the new volume, we have:

P_{1}V_{1}=P_{2}V_{2}\\\\1atm*0.125L=P_{2}*0.075L\\\\P_{2}=\frac{1atm*0.125L}{0.075l}=1.67atm

Hence, the new pressure is 1.67 atm.

Have a nice day!

7 0
3 years ago
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