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3 years ago

Acetone and sodium chloride both have similar mass. explain why their other properties differ.

Chemistry

2 answers:

romanna [79]3 years ago

8 0

Explanation:

Molecular formula of acetone is $CH_{3}COCH_{3}$ and its mass is 58.08 g/mol. Molecular formula of sodium chloride is NaCl and its mass is 58.44 g/mol.

Acetone contains ketone as the functional group and it is acidic in nature. Whereas NaCl is also known as common salt and it is not acidic in nature.

As both acetone and sodium chloride contains different type of atoms. Hence, despite of having similar mass they tend to show different properties.

dmitriy555 [2]3 years ago

5 0

<span>Acetone and sodium chloride both have similar mass but different properties. They behave in different ways since each of them consists of different atoms which has different behaviors with each other. Sodium chloride has Na and Cl atoms which are very different with acetone which has carbon, oxygen and hydrogen atoms. Hope this helps.</span>

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Answer:

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Explanation:

$Molarity=\frac{Moles}{Volume(L)}$

Molarity of the solution = 0.0366 M

Volume of the solution = 5.00 L

Moles of hydrated sodium carbonate = n

$0.0366 M=\frac{n}{5.00 L}$

$n=0.0366 M\times 5 mol=0.183 mol$

Mass of hydrated sodium carbonate = n= 52.2 g

Molar mass of hydrated sodium carbonate = 106 g/mol+x18 g/mol

$n=\frac{\text{mass of Compound}}{\text{molar mass of compound}}$

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nikitadnepr [17]

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Rhodium crystallizes in a face-centered cubic unit cell. The radius of a rhodium atom is 135 pm. Determine the density of rhodiu

Deffense [45]

Answer:

Density of unit cell ( rhodium) = 12.279 g/cm³

Explanation:

Given that:

The radius (r) of a rhodium atom = 135 pm

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For a face-centered cubic unit cell,

$r = \dfrac{a}{2\sqrt{2}}$

where;

a = edge length.

Making "a" the subject of the formula:

$a = 2 \sqrt{2} \times r$

$a = 2 \times 1.414 \times 135 \ pm$

a = 381.8 pm

to cm, we get:

a = 381.8 × 10⁻¹⁰ cm

However, recall that:

$density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}$

where;

mass of unit cell = mass of atom × numbers of atoms per unit cell

Also;

$mass\ of\ atom =\dfrac{ atomic \ mass}{Avogadro \ number}$

$mass\ of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}$

Recall also that number of atoms in a unit cell for a face-centered cubic = 4

So;

$mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4$

mass of unit cell = 6.83380375 × 10⁻²² g

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Mamont248 [21]

Answer:

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Explanation:

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to evaluate equilibrium constant for $B(g) = \frac{1}{2}A$

$K_c=[B]^2[A]$

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The equilibrium constant for $B(g) = \frac{1}{2}A$ will be

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