Answer:
The option C is the false statement
Explanation:
Ionization energy is the energy needed to completely pull out an electron from the valence electron of a gaseous atom.
The given values of ionization energy (kJmol⁻) for a main group element is: IE₁ = 100; IE₂ = 2200; IE₃ = 3300; IE₄ = 4100; IE₅ = 5200
Since<u> first ionization energy is very low</u> and the <u>difference between the first and the second ionization energy</u> for the given element is <u>very high</u>.
Therefore, <u>the given chemical element is most likely an alkali metal</u> belonging to the<u> group IA of the periodic table.</u>
As the alkali metals react with oxygen to form oxides. So, the given <u>element (J</u>) can react with oxygen to form <u>oxide of the formula J₂O</u>.
Since the given element has <u>low first ionization energy, thus it is reactive</u>. Therefore, the given element <u>can not exist as a free element.</u>
If the given chemical element belongs to <u>the period 3</u> of the periodic table, then it is should be the group IA alkali metal,<u> sodium</u>.
<u>Therefore, option C is the false statement.</u>
Alright, so this question covers the subject of spontaneous reactions. Reactions tend to be spontaneous if the products have a lower potential energy than the reactants or when the product molecules are less ordered than the reactant molecules. This may seem a little confusing but to put it simply, spontaneous reactions occur naturally.
This means there is no external force for the reaction, usually exothermic, and increases entropy. Gibbs free energy change helps us determine if the reaction is spontaneous:
delta G= delta H -T(delta S) spontaneous if delta G<0
Remember that H stands for enthalpy, or potential energy; T is for temperature; and S is entropy, the amount of disorder(spontaneous reactions increase in entropy take for ice to liquid water).
- delta H= exothermic
The reaction in the problem releases heat so the enthalpy is negative.
delta S increases with increased temperature
The entropy will be positive.
Plugging this in the Gibbs equation, you can assume delta G will be less than 0.
Therefore, the answer is B. Sorry for the long and possibly not helpful explanation. I'm learning this material currently myself. Best of luck!
<u><em>Answer:</em></u>
- The correct answer is Se^2-
<u><em>Explanation:</em></u>
- The elements of group VI-A are
- O, S, Se and Te.
- -2 is most likely form in groups VI-A elemenst like O^2- as well as S^2-. Similarly Se also have Se^2-.
<u><em>Reason:</em></u>
- Actually these elements have 6 valence shell electrons and they want to get 2 more electrons in order to get nearest configuration of noble gases.