Answer:
1) H2O
Explanation:
this is because there is a bond between two nonmetals, Hydrogen and oxygen, so the bond is covalent. all the other are bonds between a metal and nonmetal so it is ionic.
Answer:
The answer to the question is
The pressure of carbon dioxide after equilibrium is reached the second time is 0.27 atm rounded to 2 significant digits
Explanation:
To solve the question, we note that the mole ratio of the constituent is proportional to their partial pressure
At the first trial the mixture contains
3.6 atm CO
1.2 atm H₂O (g)
Total pressure = 3.6+1.2= 4.8 atm
which gives
3.36 atm CO
0.96 atm H₂O (g)
0.24 atm H₂ (g)
That is
CO+H₂O→CO(g)+H₂ (g)
therefore the mixture contained
0.24 atm CO₂ and the total pressure =
3.36+0.96+0.24+0.24 = 4.8 atm
when an extra 1.8 atm of CO is added we get Increase in the mole fraction of CO we have one mole of CO produces one mole of H₂
At equilibrium we have 0.24*0.24/(3.36*0.96) = 0.017857
adding 1.8 atm CO gives 4.46 atm hence we have
(0.24+x)(0.24+x)/(4.46-x)(0.96-x) = 0.017857
which gives x = 0.031 atm or x = -0.6183 atm
Dealing with only the positive values we have the pressure of carbon dioxide = 0.24+0.03 = 0.27 atm
Rocks are heated, metamorphosed, melted,
weathered, sediment is transported, deposited and lithified, then it may be metamorphosed
again in yet another cycle. This recycling of the material of the Earth's crust has
been going on for billions of years, as far back as there is a preserved geologic record
(about 4 billion years). Weathering and erosion at the Earth's surface can break
down rocks into small bits. These can be
deposited as sediments that become sedimentary
rocks. Burial, with rising pressure and temperature, can alter sedimentary (as well as any
other) rocks to form metamorphic rocks.
Continued rise in temperature can eventually melt
rocks and produce magma. Cooling of magmas leads to igneous rocks, etc.
Answer:
Hybridization is defined as the concept of mixing two atomic orbitals with the same energy levels to give a degenerated new type of orbitals.
