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dedylja [7]
3 years ago
13

What can make a stronger electric or magnetic field?

Physics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

add more coils

Explanation:

this increases the strength of the magnetic field

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An airplane maintains a speed of 585 km/h relative to the air it is flying through as it makes a trip to a city 815 km away to t
navik [9.2K]

Answer:

a)   t = 1.47 h    b) t = 1.32 h

Explanation:

a)  In this problem the plane and the wind are in the same North-South direction, whereby the vector sum is reduced to the scalar sum (ordinary). Let's calculate the total speed

     v = v_{f}f - v_{w}

     v = 585 -32.1

     v = 552.9 km / h

We use the speed ratio in uniform motion

     v = x / t

     t = x / v

     t = 815 /552.9

     t = 1.47 h

b)  We repeat the calculation, but this time the wind is going in the direction of the plane

      v=  v_{f}f - v_{w}

      v 585 + 32.1

      v = 617.1 km / h

      t = 815 /617.1

      t = 1.32 h

4 0
3 years ago
Acceleration usually has the symbol a. It is a vector. What is the correct way
Ghella [55]

Explanation:

a straight line under the letter

3 0
3 years ago
Determine the velocity that a car should have while traveling around a frictionless curve of radius 100m and that is banked 20 d
alex41 [277]

Answer:

v=18.89\frac{m}{s}

Explanation:

From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)

Solving N from (2) and replacing in (1):

N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c

The centripetal acceleration is given by:

a_c=\frac{v^2}{r}

Replacing and solving for v:

gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}

4 0
3 years ago
Liquids have what kind of volume and shape
Xelga [282]
A liquid has a definite volume but takes the shape of whatever object it's in.
Brainliest please! Hope this Helps!
6 0
3 years ago
A particle moving in simple harmonic motion with a period T = 1.5 s passes through the equilibrium point at time t0 = 0 with a v
ch4aika [34]

Answer

given,

Time period= T = 1.5 s

If it's moving through equilibrium point at t₀= 0 with v = 1.0 m/s

v_max=1.00 m/s

we know,

v_ max=A ω  

v = A sin (ωt)

-0.50= -1.00 sin (ωt)

sin (ωt)  =  0.5

\omega t = sin^{-1}(0.5)

\dfrac{2\pi}{T}\times t =0.524

\dfrac{2\pi}{1.5}\times t =0.524

t = 0.125 s

we have time period T=1.5 it is the time to complete one oscillation

means from eq to right,then left,then eq,then left,then from right to eq

time taken for left = t/4 = 0.125/4 = 0.375 s

smallest value of time

=0.375 + 0.125

= 0.50 sec

7 0
3 years ago
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