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Sophie [7]
3 years ago
5

Match element to how many valence electrons it has

Chemistry
1 answer:
puteri [66]3 years ago
3 0

Al - 3.

S - 6.

Mg - 2.

P - 5.

Si - 4.


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Need help with chemistry question
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This is a multiple question and here are all the answers.

Qestion 1.) Which is not a permissible set of quantum numbers? Identify the subshell (if the quantum numbers identify a possible state).

I. n = 2, ℓ = 0, mℓ = 0

II. n = 3, ℓ = 2, mℓ = 2

III. n = 2, ℓ = 1, mℓ = –1

IV. n = 3, ℓ = 3, mℓ = 0

V. n = 4, ℓ = 3, mℓ = –3

Answer:

  • The combination that is not permissible is IV. n = 3, ℓ = 3, mℓ = 0.

  • Se below to identify the subshells.

Explanation:

The electrons are identified by a set of four quantum numbers.

The first quantum number, n, is the principal quantum number and it tells the shell. The second quantum number,ℓ , is the azymuthal quantum number and it tells the subshell.

The letters used to indicate the subshells are:

  s:  ℓ  = 0

  p:  ℓ  = 1

  d:  ℓ  = 2

  f:  ℓ  = 3

The third and fourth quantum numbers are mℓ (magnetic quantum number) and s (spin).

The rules that apply to predict which quantum numbers are possible are:

  • n: 1, 2, 3, 4, 5, 6, 7 (an integer greater than 0)

  • ℓ: 0, 1, 2, 3, ..., n-1 (an integer less than n)

  • mℓ: an integer from - ℓ to + ℓ

  • s: - 1/2 or +1/2

Two electrons in an atom cannot have the same set of 4 quantum numbers.

With that:

I. n = 2, ℓ = 0, mℓ = 0

  • This combination of three quantum numbers is permissible, since n is a positive integer, ℓ is less than n, and mℓ is in the interval +ℓ  to - ℓ.

  • The combination n = 2 and ℓ = 0 means the subshell is 2p.

   

II. n = 3, ℓ = 2, mℓ = 2

  • This combination of three quantum numbers is permissible, since n is a positive integer, ℓ is less than n, and mℓ is in the interval +ℓ  to - ℓ.

  • The combination n = 3 and ℓ = 2 means the subshell is 3d.

III. n = 2, ℓ = 1, mℓ = –1

  • This combination of three quantum numbers is permissible, since n is a positive integer, ℓ is less than n, and mℓ is in the interval +ℓ  to - ℓ.

  • The combination n = 2 and ℓ = 1 means the subshell is 2p.

IV. n = 3, ℓ = 3, mℓ = 0

  • This set of three quantum numbers is not permissible, since ℓ = 3 is not less than n = 3.

V. n = 4, ℓ = 3, mℓ = –3

  • This set of three quantum numbers is permissible, since n is a positive integer, ℓ is less than n, and mℓ is in the interval +ℓ  to - ℓ.

  • The combination n = 4 and ℓ = 3 means the subshell is 4f.

Question 2.)What is the difference between the 2pz and the 3pz orbitals? Which quantum numbers in the orbital designation are different? Which will be the same? What does this indicate about the orbitals?

Answer:

The difference between    2p_z    and    3p_z    (note that the letter z is a subscript) is in the first quantum number.

The first quantum number indicates the main energy level and so it is related with the size of the orbital.

So, the 3pz orbital is bigger than the 2pz orbital.

The second quantum number is related to the letter p, so the same letter indicates the same shape of the orbital. Remember the table for the letters used to indicate the subshells are:

  s:  ℓ  = 0

  p:  ℓ  = 1

  d:  ℓ  = 2

  f:  ℓ  = 3

So, the scond quantum number for the two orbitals is ℓ  = 1.

The subscript indicates the space orientation. So, since both orbitals have the same subscript, z, they have the same orientation.

In conclusion, the only difference between those orbitals is the size of the orbitals, but they have the same shape and orientation.

3.)What is the maximum number of electrons that can have n = 3 and ms = + ½ ?

Answer:

  • 9 electrons

Explanation:

Using the rules,  for n = 3

  • ℓ can be 0, 1, or 2;

  • mℓ can be 0 for ℓ = 0,  

  • mℓ can be -1, 0, or -1 for  for ℓ = 1, and

  • mℓ can be -2, -1, 0, +1, or +2 for ℓ = 2,

You can get the possible sets of quantum numbers (with n = 3):

  • (3, 0, 0, +1/2)
  • (3, 0, 0, -1/2)
  • (3, 1, 0, +1/2)
  • (3, 1, 0, -1/2)
  • (3, 1, 1, +1/2)
  • (3, 1, 1, -1/2)
  • (3, 1, -1, +1/2)
  • (3, 1, -1, -1/2)
  • (3, 2, 0, +1/2)
  • (3, 2, 0, -1/2)
  • (3, 2, -2, +1/2)
  • (3, 2, -2, -1/2)
  • (3, 2, -1, +1/2)
  • (3, 2, -1, -1/2)
  • (3, 2, 1, +1/2)
  • (3, 2, 1, -1/2)
  • (3, 2, 2, +1/2)
  • (3, 2, 2, -1/2)

So, those are a total of 18 electrons from which half have n = 3 and ms = +1/2.

Hence, 9 electrons can have n = 3 and ms = +1/2.

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Answer:

Saturated solution

We should raise the temperature to increase the amount of glucose in the solution without adding more glucose.

Explanation:

Step 1: Calculate the mass of water

The density of water at 30°C is 0.996 g/mL. We use this data to calculate the mass corresponding to 400 mL.

400 mL \times \frac{0.996g}{1mL} =398g

Step 2: Calculate the mass of glucose per 100 g of water

550 g of glucose were added to 398 g of water. Let's calculate the mass of glucose per 100 g of water.

100gH_2O \times \frac{550gGlucose}{398gH_2O} = 138 gGlucose

Step 3: Classify the solution

The solubility represents the maximum amount of solute that can be dissolved per 100 g of water. Since the solubility of glucose is 125 g Glucose/100 g of water and we attempt to dissolve 138 g of Glucose/100 g of water, some of the Glucose will not be dissolved. The solution will have the maximum amount of solute possible so it would be saturated. We could increase the amount of glucose in the solution by raising the temperature to increase the solubility of glucose in water.

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