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Ne4ueva [31]
3 years ago
8

How many moles are equal to 5.82 x 10^23 atoms of tungsten (w)

Chemistry
2 answers:
fiasKO [112]3 years ago
6 0

Answer:

0.97 mole

Explanation:

1 mole will give 6.02×10^23 atoms

Xmole of tungsten will give 5.82×10^23 atom of tungsten

X= 5.82×10^23/ 6.02×10^23

X = 0.97 moles of tungsten

nexus9112 [7]3 years ago
4 0

Answer:

0.967 moles

Explanation:

number of moles = number of atoms / avogadro's number

We are given;

Number of atoms = 5.82×10^23

Avogadro's number = 6.02×10^23

Therefore, number of moles

= (5.82×10^23)/(6.02×10^23)

=0.967mol

Therefore, 0.967 moles are equal to 5.82×10^23 atoms

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If you clear volume in the density equation:

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The greater the density the lower the volume. This means, the volume of gold nugget will be smaller than the volume of iron pyrite nugget.

V_{gold} = \frac{m}{\rho} = \frac{50\ g}{19.3\ g/cm^3} = \bf 2.59\ cm^3

V_{iron} = \frac{m}{\rho} = \frac{50\ g}{5.0\ g/cm^3} = \bf 10\ cm^3
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3 years ago
What is the Bayer process explain it
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Answer:

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3 years ago
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iogann1982 [59]

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5 0
3 years ago
If E=mc^2,solve for both m and c. Also, if m=80 and c=0.40 what is the value of E?
Pie

<u><em>Answer:</em></u>

m = \frac{E}{c^2}

c = \sqrt{\frac{E}{m} }

E = 12.8 J

<u><em>Explanation:</em></u>

<u>Part 1: Solving for m</u>

<u>We are given that:</u>

E = mc²

To solve for m, we will need to isolate the m on one side of the equation

This means that we will simply divide both sides by c²

m = \frac{E}{c^2}

<u>Part 2: Solving for c</u>

<u>We are given that:</u>

E = mc²

To solve for c, we will need to isolate the m on one side of the equation

This means that first we will divide both sides by m and then take square root for both sides to get the value of c

c^2 = \frac{E}{m}\\  \\ c=\sqrt{\frac{E}{m}}

<u>Part 3: Solving for E</u>

<u>We are given that:</u>

m = 80 and c = 0.4

<u>To get the value of E, we will simply substitute in the given equation: </u>

E = mc²

E = (80) × (0.4)²

E = 12.8 J

Hope this helps :)

4 0
3 years ago
A container holds one mole of a gas if the amount of gas is tripled how many molecules of gas will be in the container?
Semmy [17]

Answer:At the molecular level, the pressure of a gas depends on the number of collisions its molecules have with the walls of the container. If the pressure on the piston is doubled, the volume of the gas decreases by one-half. The gas molecules, now confined in a smaller volume, collide with the walls of the container twice as often and their pressure once again equals that of the piston.

Explanation:

5 0
2 years ago
Read 2 more answers
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