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guapka [62]
3 years ago
13

Which statements accurately describe Ernest Rutherford’s experiment? Check all that apply.

Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:

The positive particles were deflected due the concentrated positive charge of the atom

Explanation:

Rutherford concluded that the positive particles were deflected through an angle greater than 90 due to electrostatic force of repulsion between the particles and positive part of the atom.

skelet666 [1.2K]3 years ago
3 0

Answer:

The correct answers are statements 1st, 4th and 5th.

Explanation:

The main observations of Ernest Rutherford's experiments are:

a. The majority of the positively charged particles passed straight through, which signifies that there is a vacant space present in the atom.  

b. However, some of the positively charged particles retraced their path.  

The deflection of the positively charged particles takes place as the like charges repel, and this shows that they got deflected by the protons. It was also found that approximately all the positive charges got concentrated in a very small section within the atom, known as nucleus.  

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Calculate the concentration (in mol/l) of 33% by weight (33 g naoh per 100 g of solution) naoh solution. (the density of the 33%
Shtirlitz [24]
Molarity is measured in moles per Liter. If there are 1.35 g/mL, find out how many grams there are in a liter of solution.

If there are 1000 mL in one liter, we can multiply by 1000 to get g/L

1.35 g/mL x 1 Liter/1000 mL = 1350 g per Liter of solution

By weight, the NaOH is 33% or .33

1350 g x .33 = 445.5 g of NaOH

Molar mass of NaOH is 39.997 g

445.5 g  x 1 mol NaOH/39.997 g = 11.13833538 moles per Liter

Rounded to significant figures, the answer is 11 mol/L NaOH


7 0
3 years ago
The size (radius) of an oxygen molecule is about 2.0 ×10−10m. Make a rough estimate of the pressure at which the finite volume o
belka [17]

Answer:

Explanation:

We can calculate the volume  of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.

We know that volume=4/3×πr³

volume =4/3×π(2.0×10⁻¹⁰m)³

volume=33.40×10⁻³⁰m³

Volume of oxygen molecule=33.40×10⁻³⁰m³

we know the ideal gas equation as:

PV=nRT

k=R/Na

R=k×Na

PV=n×k×Na×T

n×Na=N

PV=Nkt

p is pressure of gas

v is volume  of gas

T is temperature of gas

N is numbetr of molecules

Na is avagadros number

k is boltzmann constant =1.38×10⁻²³J/K

R is real gas constant

So to calculate pressure using the  formula;

PV=NkT

P=NkT/V

Since there is only one molecule of oxygen so N=1

P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³

p=12.39×10⁷Pascal

8 0
3 years ago
What are water and carbon dioxide converted into by the end of
timama [110]

Answer:

sugar and oxygen

Explanation:

In photosynthesis, solar energy is harvested as chemical energy in a process that converts water and carbon dioxide to glucose. Oxygen is released as a byproduct.

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Alenkinab [10]

The phenomenon that naturally warms the earth's lower atmosphere and surface is called the greenhouse effect.


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