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blagie [28]
3 years ago
11

A potential energy diagram is shown. What is the activation energy of this reaction?

Chemistry
1 answer:
xxMikexx [17]3 years ago
3 0

Answer:

Ea = 35 kJ.

Explanation:

Activation energy (Ea) is the difference between the potential energy of intermediate "activated complex/ peak" and reactants.

Ea = P.E. of products - P.E. of reactants = 65 kJ - 30 kJ = 35 kJ.

kindly find the attached image.

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Uhhhhhhh maybe the answer is 3
7 0
1 year ago
UU
BigorU [14]

Answer:

Samarium

Explanation:

The element Sm describe is called Samarium. This element has unique sets of properties that makes it very unique and distinct.

The lanthanides are found in the f-block on the periodic table of elements.

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7 0
3 years ago
How many grams of copper (II) nitrate would be produced from 0.80 g of copper metal reacting with excess nitric acid?
zaharov [31]

Answer:

m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2

Explanation:

Hello!

In this case, since the chemical reaction between copper and nitric acid is:

2HNO_3+Cu\rightarrow Cu(NO_3)_2+H_2

By starting with 0.80 g of copper metal (molar mass = 63.54 g/mol) and considering the 1:1 mole ratio between copper and copper (II) nitrate (molar mass = 187.56 g/mol) we can compute that mass via stoichiometry as shown below:

m_{Cu(NO_3)_2}=0.80gCu*\frac{1molCu}{63.54gCu} *\frac{1molCu(NO_3)_2}{1molCu} *\frac{187.56gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2

However, the real reaction between copper and nitric acid releases nitrogen oxide, yet it does not modify the calculations since the 1:1 mole ratio is still there:

4HNO_3+Cu\rightarrow Cu(NO_3)_2+2H_2O+2NO_2

Best regards!

7 0
3 years ago
An 80.0g sample of an unknown metal is at an initial temperature of 55.5oC. Afer 540 J of energy is absorbed by the metal, the t
Lunna [17]

Answer:

Specific heat of metal = 0.26 j/g.°C

Explanation:

Given data:

Mass of sample = 80.0 g

Initial temperature = 55.5 °C

Final temperature = 81.75 °C

Amount of heat absorbed = 540 j

Specific heat of metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  81.75 °C - 55.5 °C

ΔT =  26.25 °C

540 j = 80 g × c × 26.25 °C

540 j = 2100 g.°C× c

540 j / 2100 g.°C = c

c = 0.26 j/g.°C

7 0
3 years ago
#1: A material has a density of 8.9 g/cm^3. You have six cubic centimeters of the substance. What is the material’s mass in gram
sveta [45]
<span>The density of a material = mass/ volume From the question, volume = 6 cm^3. Since the density = 8.9 g/cm^3 We have that 8.9 = mass/ 6 So mass = 8.9 * 6 = 53.4 So it follows that our mass = 53.4g. Hence option D which is 53g.</span>
3 0
3 years ago
Read 2 more answers
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