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Vlada [557]
3 years ago
13

Which best describes the same pattern of tides on earth throughout the day?

Chemistry
2 answers:
gladu [14]3 years ago
4 0

The correct answer to this question is B.

rosijanka [135]3 years ago
3 0

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

From the given options:

<u>Option a:</u> Neap tides

Neap tides occurs when Sun and Moon form right angles with Earth. The total gravitational pull is weakened because it acts from two different directions. These tides occur twice a month. These tides have lower high tides and higher low tides.

<u>Option b:</u> Semidiurnal tides

These tides occur when two highs and two lows are of the same height. This pattern is known as semi-daily or semidiurnal tide. They show the same pattern throughout the day.

<u>Option d:</u> Spring tides

Spring tides happens when Sun, Moon and Earth, all align in the same line. The gravitational pull of Sun and Moon, both contribute to the occurrence of these tides. Hence, these tides have higher high tides and lower low tides.

From the above information, the correct answer is Option b.

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Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
Flauer [41]

Answer:

\boxed{28.81}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

1. Moles of C₄H₁₀

\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

3. Mass of CO₂

\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}

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3 years ago
WHAT TRANSPORT ULTRAVIOLET DYE THROUGH THE A/C SYSTEM?
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The balanced equation for the above reaction is;
2K + Cl₂ ---> 2KCl
Stoichiomtery of K to KCl is 2:2
Potassium is the limiting reactant which is fully consumed in the reaction. The amount of product formed depends on amount of limits reactant present.
Number of moles of K reacted - 6.75 g/ 39 g/mol = 0.17 mol
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3 years ago
If the density of a 45.0 cm3 block of wood is 0.65 g/ml what is the mass of the wood?
wlad13 [49]

Answer:

\boxed {\tt mass=29.25 \ grams}

Explanation:

The density formula is mass over volume.

d=\frac{m}{v}

Rearrange the formula for the mass, m. Multiply both sides of the formula by v.

d*v=\frac{m}{v}*v

d*v=m

Mass can be found by multiplying the density and volume. The density is 0.65 grams per milliliter and the volume is 45.0 cubic centimeters.

  • A cubic centimeter is equal to a milliliter.
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d= 0.65 \ g/mL\\v= 45 \ mL

Substitute the values into the formula.

0.65 \ g/mL * 45 \ mL=m

Multiply. Note the milliliters, or mL will cancel out.

0.65 \ g * 45=m

29.25 \ g=m

The mass of the wood is 29.25 grams.

5 0
3 years ago
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