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3 years ago

Which best describes the same pattern of tides on earth throughout the day?

Chemistry

2 answers:

gladu [14]3 years ago

4 0

The correct answer to this question is B.

rosijanka [135]3 years ago

3 0

Answer: The correct answer is Option b.

Explanation:

From the given options:

Option a: Neap tides

Neap tides occurs when Sun and Moon form right angles with Earth. The total gravitational pull is weakened because it acts from two different directions. These tides occur twice a month. These tides have lower high tides and higher low tides.

Option b: Semidiurnal tides

These tides occur when two highs and two lows are of the same height. This pattern is known as semi-daily or semidiurnal tide. They show the same pattern throughout the day.

Option d: Spring tides

Spring tides happens when Sun, Moon and Earth, all align in the same line. The gravitational pull of Sun and Moon, both contribute to the occurrence of these tides. Hence, these tides have higher high tides and lower low tides.

From the above information, the correct answer is Option b.

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Why do atoms share electrons in covalent bonds??

ra1l [238]

Atoms in covalent bonds do combine so as to be stable. As covalent bond consist non metals e.g O2 in this example each atom has vacance of 2 orbitals/ electrons so shairing electrons result their stability

6 0

3 years ago

Read 2 more answers

Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)

Brilliant_brown [7]

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) (1)

We can write the above reaction in two reactions, one for oxidation and the other for reduction:

Oxidation reaction

Li⁰(s) → Li⁺(aq) + e⁻ (2)

Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s) (3)

We can see that Li⁰ is oxidizing to Li⁺ (by losing one electron) in the lithium acetate (reaction 2) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by gaining two electrons) (reaction 3).

We must remember that the reducing agent is the one that will be oxidized by reducing another element and that the oxidizing agent is the one that will be reduced by oxidizing another species.

In reaction (1), the reducing agent is Li (it is oxidizing to Li⁺), and the oxidizing agent is Fe(CH₃COO)₂ (it is reducing to Fe⁰).

Therefore, the reducing agent in reaction (1) is lithium (Li).

Learn more here:

brainly.com/question/10547418?referrer=searchResults

brainly.com/question/14096111?referrer=searchResults

I hope it helps you!

3 0

2 years ago

A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL

ziro4ka [17]

Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

V = 0.022 * 0.082 * 296.15 / 0.967

V = 0.552 L or 552 mL

This is the volume that hydrogen occupies.

6 0

3 years ago

The diameter of metal wire is often referred to by its American wire-gauge number. A 16 gauge-wire has a diameter of 0.05082 in.

lubasha [3.4K]

Answer:

length of wire = 38.82 m

Explanation:

∴ 16 gauge ≡ 0.05082 in * ( 2.54 cm/in ) = 0.12908 cm

∴ m spool = 1 Lb = 453.592 g

∴ ρ = 8.92 g/cm³

cross section area:

⇒ A = π*D²/4 = π*(0.12908)²/4 = 0.0131 cm²

⇒ L = ((453.592 g) *(cm³/8.92 g)) / ( 0.0131 cm² )

⇒ L = 3881.765 cm * ( m/100cm) = 38.82 m

8 0

3 years ago

What two elements fill their last electron in the 5s sublevel?

postnew [5]

Answer:Rubidium and Strontium

Explanation:

7 0

3 years ago