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2 years ago

What kinds of compounds have the greatest difference between their melting point and their boiling point?

1 answer:

3 0

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The specific heat of copper is 0.40 joules/ g °c. How much heat is needed in joules to change the temperature of a 55 gram subst

Snezhnost [94]

Answer : The amount of heat needed is, 1188 J

Explanation :

Formula used :

$q=m\times c\times (T_2-T_1)$

where,

q = heat needed = ?

m = mass of copper = 55 g

c = specific heat capacity of copper = $0.40J/g^oC$

$T_1$ = initial temperature = $20.0^oC$

$T_2$ = final temperature = $74.0^oC$

Now put all the given values in the above formula, we get:

$q=55g\times 0.40J/g^oC\times (74.0-20.0)^oC$

$q=1188J$

Thus, the amount of heat needed is, 1188 J

3 0

2 years ago

Sulfur burns in the air to form 33.6L of sulfur dioxide. (S = 32, O =16, 64g of sulfur dioxide has 22.4L, 32g of oxygen has 22.4

ivolga24 [154]

The mass of oxygen reacted/required in this reaction is obtained as 48g.

<h3>What is stoichiometry?</h3>

The term stoichiometry has to do with mass- volume or mass - mole relationship which ultimately depends on the balanced reaction equation.

Now, we have the reaction; S + O2 ------>SO2

If 1 mole of sulfur dioxide contains 22.4 L

x moles of sulfur dioxide contains 33.6L

x = 1.5 moles of sulfur dioxide.

Since the reaction is 1:1, the number if moles of oxygen required/reacted is 1.5 moles.

Mass of oxygen required/reacted = 1.5 moles * 32 g/mol = 48g

Learn more anout stoichiometry: brainly.com/question/9743981

8 0

1 year ago

How many protons, neutrons, and electrons does gold have? I need to know how many protons, neutrons, and electrons the element g

zhuklara [117]

Protons: 79
neutrons: 118
electrons: 79

4 0

2 years ago

In cellular respiration glucose is oxidized to three compounds

7nadin3 [17]

CO2 + H2O + Energy are the comments

7 0

2 years ago

? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2

Novay_Z [31]

Data:
$M_{concentrated} = 2.5\:mol$
$V_{concentrated} = ?$
$M_{dilute} = 0.50\:mol$
$V_{dilute} = 100\:mL\to0.100\:L$
<span>
Formula: Dilution Calculations

</span> $M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}$
<span>
Solving:

</span>
$M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}$
$2.5 * V_{concentrated} = 0.50 * 0.100$
$2.5V_{concentrated} = 0.05$
$V_{concentrated} = \frac{0.05}{2.5}$
$\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark$ <span>

</span>

3 0

2 years ago