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Nataly_w [17]
3 years ago
6

Convert 325 milliliters to liters.

Chemistry
2 answers:
nikitadnepr [17]3 years ago
5 0

Answer:

.b

Explanation:b

.

AlekseyPX3 years ago
4 0

Answer:

The Awnser Is A. 0.325 Liters

Explanation:

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133.0873 g/mol

(NH4)3PO3 - molar mass
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When a 10 mL graduated cylinder is filled to the 10 mL mark, the mass of the water was measured to be 9.925 g. If the density of
Vlada [557]
Measured volume = 10 ml 
mass = 9.925 g 
density = 0.9975 g/ml
density = \frac{mass}{volume} 
so actual volume = \frac{mass}{density} = \frac{9.925}{0.9975} = 9.95 mL
Percentage Error = \frac{measured volume - Actual volume}{actual volume} x 100 
= \frac{10 - 9.95}{9.95} x 100 = 0.5 % error
5 0
3 years ago
Use bond energies to calculate the enthalpy of reaction for the combustion of ethane. Average bond energies in kJ/mol C-C 347, C
ivanzaharov [21]

The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.

The reaction is:

2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O  (1)  

The enthalpy of reaction (1) is given by:

\Delta H = \Delta H_{r} - \Delta H_{p}   (2)

Where:

r: is for reactants

p: is for products

The bonds of the compounds of reaction (1) are:

  • 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
  • 7O₂: 7 moles of 1 O=O bond  
  • 4CO₂: 4 moles of 2 C=O bonds  
  • 6H₂O: 6 moles of 2 H-O bonds

Hence, the enthalpy of reaction (1) is (eq 2):

\Delta H = \Delta H_{r} - \Delta H_{p}

\Delta H = 2*\Delta H_{CH_{3}CH_{3}} + 7\Delta H_{O_{2}} - (4*\Delta H_{CO_{2}} + 6*\Delta H_{H_{2}O})      

\Delta H = 2*(6*\Delta H_{C-H} + \Delta H_{C-C}) + 7\Delta H_{O=O} - (4*2*\Delta H_{C=O} + 6*2*\Delta H_{H-O})  

\Delta H = [2*(6*413 + 347) + 7*498 - (4*2*799 + 6*2*467)] kJ/mol  

\Delta H = -2860 kJ/mol          

Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.

Read more here:

brainly.com/question/11753370?referrer=searchResults  

I hope it helps you!        

7 0
2 years ago
A student isolated 15.6 g of product from a chemical reaction. She calculated that the reactions should have produced 18.4 g of
Snezhnost [94]

Answer:

The percent yield of this reaction is 84.8 % (option A is correct)

Explanation:

Step 1: Data given

The student isolated 15.6 grams of the product = the actual yield

She calculated the reaction should have produced 18.4 grams of product = the theoretical yield = 18.4 grams

Step 2: Calculate the percent yield

Percent yield = (actual yield / theoretical yield ) * 100 %

Percent yield = (15.6 grams / 18.4 grams ) * 100 %

Percent yield  = 84.8 %

The percent yield of this reaction is 84.8 % (option A is correct)

7 0
3 years ago
What is subshell and why do we use it if we have main shells already
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Principal shell shows the main energy level, in that there are some more energy levels. This is how the atomic structure is defined according to the Quantum Mechanical model of atom. So exactly why do subshells exist and all i don't know
5 0
3 years ago
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