Answer:
1.) To convert between grams and moles, you would use the substance's molar mass. To go from grams to moles, divide the grams by the molar mass. 600 g58.443 g/mol = 10.27 mol of NaCl. It has been found that 1 mol of any gas at STP (Standard Temperature and Pressure = 0 °C and 1 atm) occupies 22.4 L
Answer:
That's easier for you to come over and watch the answer to the question
Answer:
1632 Hz
Explanation:
We'll begin by calculating the frequency of each wave. This can be obtained as follow:
1st wave:
Velocity (v) = 340 m/s.
Wavelength 1 (λ₁) = 5 m
Frequency 1 (f₁) =?
v = λ₁f₁
340 = 5 × f₁
Divide both side by 5
f₁ = 340 / 5
f₁ = 68 Hz
2nd wave:
Velocity (v) = 340 m/s.
Wavelength 2 (λ₂) = 0.2 m
Frequency 2 (f₂) =?
v = λ₂f₂
340 = 0.2 × f₂
Divide both side by 0.2
f₂ = 340 / 0.2
f₂ = 1700 Hz
Finally, we shall determine the difference in the frequency of both waves.
This can be obtained as follow:
Frequency 1 (f₁) = 68 Hz
Frequency 2 (f₂) = 1700 Hz
Difference =?
Difference = f₂ – f₁
Difference = 1700 – 68
Difference = 1632 Hz
Answer:
Explanation:
1 standard deviation range will look like: [average - SD, average + SD]
Here the miximum value will be: average - SD = 2.6 - 0.80 = 1.80 ml
and the maximum value will be: average + SD = 2.6 + 0.80 = 3.40ml
Answer:
The volume of hydrochloric acid increases.
Explanation:
- Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
- Increasing the volume of water vapors:
will increase the the concentration of the products side, so the reaction will be shifted to the left side (backward) to suppress the increase in the concentration of water vapors by addition.
So, The volume of hydrochloric acid increases, the rate of backward reaction increases, the rate of forward reaction decreases, and the volume of chlorine decreases.
<em>So, the right choice is: The volume of hydrochloric acid increases.</em>
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