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Ivenika [448]
3 years ago
6

Factor completely x3 + 7x2 − 2x − 14.

Mathematics
2 answers:
Lapatulllka [165]3 years ago
8 0

Answer:

(x+7)(x^2-2)

Step-by-step explanation:

x^3 + 7x^2 − 2x − 14

We will factor by grouping

Take x^2 out of the first two terms and -2 out of the last 2 terms

x^2(x+7) -2(x+7)

Now we can factor out (x+7)

(x+7)(x^2-2)

frutty [35]3 years ago
3 0

Answer:

the factors of x3 + 7x2 − 2x − 14. are (x^2-2)(x+7)....

Step-by-step explanation:

x3 + 7x2 − 2x − 14.

We will group the terms.

Make pairs of the terms:

(x3 + 7x2 ) - (2x + 14.)

Now find the common factor of each pair

x^2(x+7)-2(x+7)

(x^2-2)(x+7)

Thus the factors of x3 + 7x2 − 2x − 14. are (x^2-2)(x+7)....

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Answer:

Step-by-step explanation:

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Now usually we'd we simply solve for X.

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A rectangle's length is 3 feet longer than its width. its perimeter is 62 feet
DanielleElmas [232]

Hi!

<h3>The perimeter is equal to </h3>

<u>l + l + w + w = 62</u>

<h3>The length is 3 feet longer than the width so...</h3>

<u>w + 3 + w + 3 + w + w = 62</u>

<h3>Simplify</h3>

<u>4w + 6 = 62</u>

4w + 6 - 6 = 62 - 6

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<h2>The width is 14 and the length is 17. </h2>

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Transform each polar equation to an equation in rectangular coordinates and identify its shape.
Gemiola [76]

Answer:

(a) x ^ 2 + y ^ 2 = 6 ^ 2

(b) (x-1) ^ 2 + y ^ 2 = 1

Step-by-step explanation:

Remember that to convert from polar to rectangular coordinates you must use the relationship:

x = rcos(\theta)

y = rsin(\theta)

x ^ 2 + y ^ 2 = r ^ 2

In this case we have the following equations in polar coordinates.

(a) r = 6.

Note that in this equation the radius is constant, it does not  depend on \theta.

As r ^ 2 = x ^ 2 + y ^ 2

Then we replace the value of the radius in the equation and we have to::

x ^ 2 + y ^ 2 = 6 ^ 2

Then r = 6 in rectangular coordinates is a circle centered on the point (0,0) and with a constant radius r = 6.

(b) r = 2cos(\theta)

The radius is not constant, the radius depends on \theta.

To convert this equation to rectangular coordinates we write

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r ^ 2 = 2x        <em>remember that </em>x ^ 2 + y ^ 2 = r ^ 2, <em>then:</em>

x ^ 2 + y ^ 2 = 2x         <em>Simplify the expression. </em>

x ^ 2 -2x + y ^ 2 = 0     <em>Complete the square. </em>

x ^ 2 -2x + 1 + y ^ 2 = 1

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3 years ago
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