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Anni [7]
3 years ago
12

If a positively charged ion is more concentrated outside the cell, the forces required to balance the chemical gradient would be

directed ________. Thus, the equilibrium potential for this ion would be ________ charged. If a positively charged ion is more concentrated outside the cell, the forces required to balance the chemical gradient would be directed ________. Thus, the equilibrium potential for this ion would be ________ charged. inward : negatively outward : positively outward : neutrally inward : positively outward : negatively
Physics
2 answers:
galben [10]3 years ago
8 0

Answer: If a positively charged ion is more concentrated outside the cell, the forces required to balance the chemical gradient would be directed OUTWARD. Thus, the equilibrium potential for this ion would be POSITIVELY charged. The correct answer is OUTWARD: POSITIVELY.

Explanation: Usually across a cell membrane there is a force that acts on it which is as a result of unequal distribution of charges. This force is known as electrochemical driving force. It is determined by the difference between the membrane potential ( that is, the electrical potential difference across the cell membrane) and the ion equilibrium potential. The membrane potential of a cell helps in signal transmission between different parts of the cell and results when there is unequal distribution across the cell.

Therefore If a positively charged ion is more concentrated outside the cell, the forces required to balance the chemical gradient would be directed outward.Thus, the equilibrium potential for this ion would be positively charged.

antoniya [11.8K]3 years ago
8 0

Answer:

Inward:negatively

Explanation:

This question is duplicated making it incorrectly asked. The correct question is:

If a positively charged ion is more concentrated outside the cell, the forces required to balance the chemical gradient would be directed ________. Thus, the equilibrium potential for this ion would be ________ charged.

inward : negatively, outward : positively, outward : neutrally, inward : positively, outward : negatively

The answer is Inward:negatively

Chemical gradient across a cell or biological membrane is the gradient of the concentration of the ions in the cell or the membrane. To balance the chemical gradient across a cell, an equal force in an opposite direction is required and equilibrium potential must be zero. For instance a positive charge ion more concentrated outside the cell will require a force directed inwardly with a negative charge ion to neutralise the positive charge ion

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A mixture is a physical combination of 2 or more substances that are blended together without forming a new substance.

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Joe and Max shake hands and say goodbye. Joe walks east 0.40 km to a coffee shop, and Max flags a cab and rides north 3.65 km to
katen-ka-za [31]

Answer:

3.67 km

Explanation:

Joe distance towards coffee shop is,

OB=0.40 km

And the Max distance towards bookstore is,

OA=3.65 km

Now the distance between the Joy and Max will be,

By applying pythagorus theorem,

AB=\sqrt{OB^{2}+OA^{2}}

Substitute 0.40 km for OB and 3.65 km for OA in the above equation.

AB=\sqrt{0.40^{2}+3.65^{2}}\\AB=\sqrt{13.4825} \\AB=3.67 km

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6 0
3 years ago
A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar
notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2>\omega = 0.23 rad/s</h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

L_i = L_f

now we can say

m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega

so we will have

0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega

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Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

6 0
3 years ago
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