Answer:
Jesseca wanted to create a material that reflected most of the light that fell on it.
Explanation:
Plato Answer
Answer:
P=9.58 W
Explanation:
According to Newton's second law, and assuming friction force as zero:
![F_m=m.a\\F_m=0.875kg*a](https://tex.z-dn.net/?f=F_m%3Dm.a%5C%5CF_m%3D0.875kg%2Aa)
The acceleration is given by:
![a=\frac{\Delta v}{t}\\a=\frac{0.685m/s}{21.5*10^{-3}s}\\\\a=31.9m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B%5CDelta%20v%7D%7Bt%7D%5C%5Ca%3D%5Cfrac%7B0.685m%2Fs%7D%7B21.5%2A10%5E%7B-3%7Ds%7D%5C%5C%5C%5Ca%3D31.9m%2Fs%5E2)
So the force exerted by the motor is:
![F_m=0.875kg*31.9m/s^2\\F_m=27.9N](https://tex.z-dn.net/?f=F_m%3D0.875kg%2A31.9m%2Fs%5E2%5C%5CF_m%3D27.9N)
The work done by the motor is given by:
![W_m=F_m*d\\\\d=\frac{1}{2}*a*t^2\\d=\frac{1}{2}*31.9m/s^2*(21.5*10^{-3}s)^2\\\\d=7.37*10^{-3}m](https://tex.z-dn.net/?f=W_m%3DF_m%2Ad%5C%5C%5C%5Cd%3D%5Cfrac%7B1%7D%7B2%7D%2Aa%2At%5E2%5C%5Cd%3D%5Cfrac%7B1%7D%7B2%7D%2A31.9m%2Fs%5E2%2A%2821.5%2A10%5E%7B-3%7Ds%29%5E2%5C%5C%5C%5Cd%3D7.37%2A10%5E%7B-3%7Dm)
![W_m=27.9N*7.37*10^{-3}m\\W_m=0.206J](https://tex.z-dn.net/?f=W_m%3D27.9N%2A7.37%2A10%5E%7B-3%7Dm%5C%5CW_m%3D0.206J)
And finally, the power is given by:
![P=\frac{W_m}{t}\\P=\frac{0.206J}{21.5*10^{-3}s}\\\\P=9.58W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BW_m%7D%7Bt%7D%5C%5CP%3D%5Cfrac%7B0.206J%7D%7B21.5%2A10%5E%7B-3%7Ds%7D%5C%5C%5C%5CP%3D9.58W)
Mars is 139.58 million miles away from the sun. mars is red because its soil has iron oxide (rust particles) in it.
C. Clear, dry weather. A good way to remember is H for high pressure = H for happy weather; L for low pressure = L for lousy weather (Glad I had someone to tell me this)
<h2>
Answer:53.63![ms^{-2}](https://tex.z-dn.net/?f=ms%5E%7B-2%7D)
</h2>
Explanation:
The equations of motion used in this question is ![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
When a object is projected horizontally from a sufficiently height,the x-component of acceleration remains zero because there is no force that drags the object in x direction.
But,due to gravity,the object accelerates downward at a rate of
.
In X-Direction,
Given that initial velocity=
=![33.8ms^{-1}](https://tex.z-dn.net/?f=33.8ms%5E%7B-1%7D)
Using
,
![v_{x}=33.8+(0)4.25=33.8ms^{-1}](https://tex.z-dn.net/?f=v_%7Bx%7D%3D33.8%2B%280%294.25%3D33.8ms%5E%7B-1%7D)
In Y-Direction,
Given that initial velocity=
=![0ms^{-1}](https://tex.z-dn.net/?f=0ms%5E%7B-1%7D)
Using
,
![v_{y}=0+(9.8)4.25=41.65ms^{-1}](https://tex.z-dn.net/?f=v_%7By%7D%3D0%2B%289.8%294.25%3D41.65ms%5E%7B-1%7D)
![v=\sqrt{v_{x}^{2}+v_{y}^{2}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bv_%7Bx%7D%5E%7B2%7D%2Bv_%7By%7D%5E%7B2%7D%7D)
![v=\sqrt{1142.44+1734.72}=\sqrt{2877.163}=53.63ms^{-1}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B1142.44%2B1734.72%7D%3D%5Csqrt%7B2877.163%7D%3D53.63ms%5E%7B-1%7D)