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3 years ago

If a distance-time graph contains the point (4, 15), what does that tell you about the runner?

Physics

1 answer:

serg [7]3 years ago

5 0

Explanation:

It is given that there is distance time graph. The slope of any distance time graph will give the speed or velocity of the object.

In the context, it is seen that there is a point in the distance - time graph. And the values of the point in the graph is (4,15).

Now here, the distance is plotted in the ordinate or the vertical y-axis while time is plotted in the abscissa or the horizontal x-axis.

Thus the point (4,15) tells us that the object has traveled 15 units in time equal to 4 seconds.

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To provide some perspective on the dimensions of atomic defects, consider a metal specimen that has a dislocation density of 105

-Dominant- [34]

Explanation:

LD₁ = 10⁵ mm⁻²

LD₂ = 10⁴mm⁻²

V = 1000 mm³

Distance = (LD)(V)

Distance₁ = (10⁵mm⁻²)(1000mm³) = 10×10⁷mm = 10×10⁴m

Distance₂ = (10⁹mm⁻²)(1000mm³) = 1×10¹² mm = 1×10⁹ m

Conversion to miles:

Distance₁ = 10×10⁴ m / 1609m = 62 miles

Distance₂ = 10×10⁹m / 1609 m = 621,504 miles.

7 0

3 years ago

Read 2 more answers

A wire carrying a current of 26.9 A is bent into a circular arc with a radius of 0.6 cm that sweeps out 0.900 radians. What is t

melomori [17]

The magnetic field at the center of the arc is 4 × 10^(-4) T.

To find the answer, we need to know about the magnetic field due to a circular arc.

<h3>What's the mathematical expression of magnetic field at the center of a circular arc?</h3>

According to Biot savert's law, magnetic field at the center of a circular arc is

B=(μ₀ I/4π)× (arc/radius²)

As arc is given as angle × radius, so

B=( μ₀I/4π)×(angle/radius)

<h3>What will be the magnetic field at the center of a circular arc, if the arc has current 26.9 A, radius 0.6 cm and angle 0.9 radian?</h3>

B=(μ₀ I/4π)× (0.9/0.006)

= (10^(-7)× 26.9)× (0.9/0.006)

= 4 × 10^(-4) T

Thus, we can conclude that the magnitude of magnetic field at the center of the circular arc is 4 × 10^(-4) T.

Learn more about the magnetic field of a circular arc here:

brainly.com/question/15259752

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5 0

2 years ago

Capacitor 2 has half the capacitance and twice the potential difference as capacitor 1. What is the ratio (U_{\rm C})_1/\,(U_{\r

IrinaK [193]

Answer:

1/2

Explanation:

The energy stored in a capacitor is given by

$U=\frac{1}{2}CV^2$

where

C is the capacitance

V is the potential difference

Calling $C_1$ the capacitance of capacitor 1 and $V_1$ its potential difference, the energy stored in capacitor 1 is

$U=\frac{1}{2}C_1 V_1^2$

For capacitor 2, we have:

- The capacitance is half that of capacitor 1: $C_2 = \frac{C_1}{2}$

- The voltage is twice the voltage of capacitor 1: $V_2 = 2 V_1$

so the energy stored in capacitor 2 is

$U_2 = \frac{1}{2}C_2 V_2^2 = \frac{1}{2}\frac{C_1}{2}(2V_1)^2 = C_1 V_1^2$

So the ratio between the two energies is

$\frac{U_1}{U_2}=\frac{\frac{1}{2}C_1 V_1^2}{C_1 V_1^2}=\frac{1}{2}$

4 0

3 years ago

What scale can I use for two force 0.8 Newtons and 0.9 Newtons? Someone please help

kirill [66]

Answer:

Explanation:

To plot the given forces of 0.8 N and 0.9 N. It is convenient to take

0.1 N as 1 unit in Graph

For example, 1 unit in the graph is 1 cm

then take 0.1 N equivalent to 1 cm

$0.8 N\equiv 8\ \text{units in graph}\\\\0.9\equiv 9\ \text{units in graph}$

5 0

3 years ago

Physics - Wave Diagrams Assignment<br>Wave<br>Wave<br>B<br>CAN SOMEONE HELP ME LOL

Oxana [17]

Answer:At the top of the page is a transvers wave

C= crest

B= wavelingth

D= trough

A= amplatud

The next wave is a longitudinal wave

3 0

3 years ago