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3 years ago

If a distance-time graph contains the point (4, 15), what does that tell you about the runner?

Physics

1 answer:

serg [7]3 years ago

5 0

Explanation:

It is given that there is distance time graph. The slope of any distance time graph will give the speed or velocity of the object.

In the context, it is seen that there is a point in the distance - time graph. And the values of the point in the graph is (4,15).

Now here, the distance is plotted in the ordinate or the vertical y-axis while time is plotted in the abscissa or the horizontal x-axis.

Thus the point (4,15) tells us that the object has traveled 15 units in time equal to 4 seconds.

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1 hour = 3600 seconds.
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3 years ago

What is the relationship between acceleration and time?

Harlamova29_29 [7]

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3 years ago

The heating element in a kettle behaves like a resistor. A particular kettle needs to operate at 230 V, with a power of 1500 W.

dedylja [7]

Answer:

R = 35.27 Ohms

Explanation:

Given the following data;

Voltage = 230V

Power = 1500W

To find the resistance, R;

Power = V²/R

Where:

V is the voltage measured in volts.

R is the resistance measured in ohms.

Substituting into the equation, we have;

1500 = 230²/R

Cross-multiplying, we have;

1500R = 52900

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R = 35.27 Ohms.

Therefore, the resistance which the heating element needs to have is 35.27 Ohms.

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2 years ago

Which statement is true? A Displacement can never be greater than distance. B Displacement can never be less than distance. C Di

qwelly [4]

Answer:

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I think the answer is A.

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3 years ago

When Jim and Rob ride bicycles, Jim can only accelerate at three-quarters the acceleration of Rob. Both startfrom rest at the bo

Natali5045456 [20]

Answer:

46.4 s

Explanation:

5 minutes = 60 * 5 = 300 seconds

Let g = 9.8 m/s2. And $\theta$ be the slope of the road, s be the distance of the road, a be the acceleration generated by Rob, 3a/4 is the acceleration generated by Jim . Both of their motions are subjected to parallel component of the gravitational acceleration $gsin\theta$