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Margarita [4]
3 years ago
10

For states with larger values of n that admit a d subshell, the d subshell is at even higher energy than the p subshell. In fact

, its energy is higher than that of the s subshell for the n+1 state. With this in mind, which of the following are valid ground-state electron structures?1. 1s2 2s2 2p63 s2 3p6 3d22. 1s2 2s2 2p6 3s2 3p6 3d113. 1s2 2s2 2p6 3s2 3p6 4s2 3d5A. 1B. 2C. 3D. 1 and 2E. 1 and 3F. 2 and 3
Physics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

Explanation:

Correct order of energy of energy states within an atom is as follows

1s , 2 s, 2 p 3 s ,3 p, 4s , 3d,  4p, 4p,5s etc.

There is discrepancies in this order due to overlapping of outer orbitals with inner orbitals so sometimes outer orbitals have lower energy.

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During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive
Katyanochek1 [597]

Answer:

The force is F = 1041.7N

Explanation:

The moment of Inertia I is mathematically evaluated as

               I = MR_A^2

Substituting  1.9kg for M(Mass of the wheel) and \frac{66cm}{2} * \frac{1m}{100cm} = 0.33m for R_A(Radius of wheel)

              I = 1.9 * 0.33^2

                = 0.207kgm^2

The torque on the wheel due to net force is mathematically represented as

                      \tau = FR_B  - F_rR_A

Substituting  135 N for F_r (Force acting on sprocket),\frac{8.7cm}{2} * \frac{1m}{100cm} = 0.0435m for R_B (radius of the chain) and F is the force acting on the sprocket due to the chain which is unknown for now

                     \tau = F (0.0435) - 135 (0.33)

This same torque due to the net force is the also the torque that is required to rotate the wheel to have an angular acceleration of \alpha  = 3.70 rad/s^2 and this torque can also be represented mathematically as

                   \tau = \alpha I

Now equating the two equation for torque

                                F (0.0435) - 135 (0.33) = \alpha I    

Making F the subject

                     F = \frac{\alpha I + (135*0.33) }{0.0435}

Substituting values

                  F = \frac{(3.70 * 0.207)  + (135*0.33)}{0.0435}

                       = 1041.7N

4 0
2 years ago
What is the smallest accurate measurement that can be made with an instrument?
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Dependent on what you are measuring and what took you are using. Please be more specific.
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3 years ago
The position-time graph for a bug crawling along a line is shown in item 4 below. Determine whether the velocity is positive, ne
Naddika [18.5K]

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t1 = -

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What is kirchoff s law???
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