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Margarita [4]
3 years ago
10

For states with larger values of n that admit a d subshell, the d subshell is at even higher energy than the p subshell. In fact

, its energy is higher than that of the s subshell for the n+1 state. With this in mind, which of the following are valid ground-state electron structures?1. 1s2 2s2 2p63 s2 3p6 3d22. 1s2 2s2 2p6 3s2 3p6 3d113. 1s2 2s2 2p6 3s2 3p6 4s2 3d5A. 1B. 2C. 3D. 1 and 2E. 1 and 3F. 2 and 3
Physics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

Explanation:

Correct order of energy of energy states within an atom is as follows

1s , 2 s, 2 p 3 s ,3 p, 4s , 3d,  4p, 4p,5s etc.

There is discrepancies in this order due to overlapping of outer orbitals with inner orbitals so sometimes outer orbitals have lower energy.

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Answer:

1.07 nT

Explanation:

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So, B = E/c

Substituting E and c into B, we have

B = E/c

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= 0.1067 × 10⁻⁸ T

= 1.067 × 10⁻⁹ T

= 1.067 nT

≅ 1.07 nT

3 0
3 years ago
_____ have played a major role in altering Earth's atmospheric composition over time.A. TsunamisB. VolcanoesC. HurricanesD. Eart
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Un lector de DVD, la velocidad de giro es de 5400 rpm. determina el valor velocidad angular en rad/s,la frecuencia y el periodo
zubka84 [21]

Responder:

A) ω = 565.56 rad / seg

B) f = 90Hz

C) 0.011111s

Explicación:

Dado que:

Velocidad = 5400 rpm (revolución por minuto)

La velocidad angular (ω) = 2πf

Donde f = frecuencia

ω = 5400 rev / minuto

1 minuto = 60 segundos

2πrad = I revolución

Por lo tanto,

ω = 5400 * (rev / min) * (1 min / 60s) * (2πrad / 1 rev)

ω = (5400 * 2πrad) / 60 s

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ω = 180πrad / seg

ω = 565.56 rad / seg

SI)

Dado que :

ω = 2πf

donde f = frecuencia, ω = velocidad angular en rad / s

f = ω / 2π

f = 565.56 / 2π

f = 90.011669

f = 90 Hz

C) Periodo (T)

Recordar T = 1 / f

Por lo tanto,

T = 1/90

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3 years ago
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Answer:

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Explanation:

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Suppose that the acceleration of a model rocket is proportional to the difference between 100 ft/sec and the rocket's velocity.
sp2606 [1]

Answer:

Explanation:

initial velocity, u = 0

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