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mixas84 [53]
3 years ago
15

As a rock sinks deeper and deeper into water of constant density, what happens to the buoyant force on it? As a rock sinks deepe

r and deeper into water of constant density, what happens to the buoyant force on it? It increases. It may increase or decrease, depending on the shape of the rock. It may increase or decrease, depending on the weight of the rock. It remains constant. It decreases. g
Physics
1 answer:
Sidana [21]3 years ago
3 0

Answer:

It remains constant

Explanation:

As we know that buoyant force on an object given as

Fb = ρ Vd g

ρ= Density of fluid

Vd=Volume displace by body

g=10 m/s²

Fb =buoyant force

So from above we can say that buoyant force does not depends on the depth. It only depends on the fluid density and volume displace by body.

So when rock gets deeper and deeper the buoyant force will remain constant.

It remains constant

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Explanation:

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soldi70 [24.7K]

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t = 0.029s

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In order to calculate the interaction time at the moment of catching the ball, you take into account that the force exerted on an object is also given by the change, on time, of its linear momentum:

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