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nata0808 [166]
3 years ago
7

Which scientist performed the cathode ray experiment leading to the discovery of electrons?

Chemistry
2 answers:
Mrrafil [7]3 years ago
8 0

Answer:

E. Thomson

Explanation:

J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons.

https://www.khanacademy.org/science/chemistry/electronic-structure-of-atoms/history-of-atomic-structure/a/discovery-of-the-electron-and-nucleus

sweet [91]3 years ago
5 0
<h2>Answer:</h2>

The scientist is <u>E. Thomson </u>.

<h2>Explanation:</h2>

In the late nineteenth century, physicist J.J. Thomson started trying different things with cathode beam tubes. Cathode beam cylinders are fixed glass tubes from which the greater part of the air has been emptied. A high voltage is applied crosswise over two terminals toward one side of the cylinder, which makes a light emission stream from the cathode (the contrarily charged anode) to the anode (the emphatically charged cathode).

The cylinders are called cathode beam tubes on the grounds that the molecule bars or “cathode beam” begins at the cathode. The beam can be distinguished by painting a material known as phosphors onto the most distant finish of the cylinder past the anode. The phosphors sparkles, or produces light, when affected by the cathode beam.

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3 years ago
Magnesium metal (0.100 mol) and a volume of aqueous hydrochloric acid that contains 0.500 mol of HCl are combined and react to c
jok3333 [9.3K]

Answer:

2.24 L of hydrogen gas, measured at STP, are produced.

Explanation:

Given, Moles of magnesium metal, Mg = 0.100 mol

Moles of hydrochloric acid, HCl = 0.500 mol

According to the reaction shown below:-

Mg_{(s)} + 2HCl_{(aq)}\rightarrow MgCl_2_{(aq)} + H_2_{(g)}

1 mole of Mg reacts with 2 moles of HCl

0.100 mol of Mg reacts with 2*0.100 mol of HCl

Moles of HCl must react = 0.200 mol

Available moles of HCl = 0.500 moles

Limiting reagent is the one which is present in small amount. Thus, Mg is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of Mg on reaction forms 1 mole of H_2

0.100 mole of Mg on reaction forms 0.100 mole of H_2

Mole of H_2 = 0.100 mol

At STP,  

Pressure = 1 atm  

Temperature = 273.15 K

Volume = ?

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V L = 0.100 × 0.0821 L.atm/K.mol × 273.15 K  

<u>⇒V = 2.24 L</u>

2.24 L of hydrogen gas, measured at STP, are produced.

4 0
3 years ago
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