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kvv77 [185]
3 years ago
6

Give the location of the elements found in the periodic table which have the same number valence electrons.

Chemistry
2 answers:
Rina8888 [55]3 years ago
7 0

Answer:

B - all numbers within any group (vertical column)

Explanation:

https://en.wikipedia.org/wiki/Valence_electron

stiks02 [169]3 years ago
5 0

Answer:

B - all numbers within any group

Explanation:

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Convert the following to scientific notation 24,212,000
UNO [17]
2.4212 X 10^ 7
How I at least figure this problem out is I take a pencil and start on the right side of the 0 and make a loop to the left for each number and count until I get to the first two numbers that are between 1-9 when reading from left to right. This is where you put the decimal point. Some teachers rather you keep the 0's there, while others prefer one to get rid of them. Anyways with that new decimal number, you multiply the decimal by ten to what ever number you counted, which was 7.
5 0
3 years ago
Name three sources of CO2
dangina [55]

Answer:

1.Respiration of animals and plants.

2.The burning of fossil fuels.

3.Bacteria decompose corpses.

4 0
3 years ago
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How many moles of oxygen atoms are in 7.9E-1 moles of CO_2
Ilya [14]

Answer:

The number of moles of O atom in (7.9\times10^{-1}) mol of CO_{2} = 1.6

Explanation:

1 molecule of CO_{2} contains 2 atoms of O

So, (6.023\times 10^{23}) molecules of  CO_{2} contains (2\times6.023\times10^{23}) atoms of O.

We know that 1 mol of an atom/molecule/ion represents 6.023\times10^{23} numbers of atoms/molecules/ions respectively.

So, (6.023\times 10^{23}) molecules of  CO_{2} is equal to 1 mol of CO_{2}.

(2\times6.023\times10^{23}) atoms of O is equal to 2 moles of O atom.

Hence, 1 mol of CO_{2} contains 2 moles of O atom.

Therefore, (7.9\times10^{-1}) mol of CO_{2} contains (2\times7.9\times10^{-1}) moles of O atom or 1.6 moles of O atom.

3 0
3 years ago
Provide the organometallic reagent that is needed to perform the transformation shown below. The reagent should be formatted as
Juliette [100K]

The correct answer is   LiCH_{3}CH(CH_{3} )CH_{3} .

<h3>Organometallic reagent</h3>

Organometallic chemistry is the study of organometallic compounds, which are substances that contain at least one chemical bond between a carbon atom from an organic molecule and a metal. These substances include alkali, alkaline earth, and transition metals, as well as metalloids like boron, silicon, and selenium. In addition to links to organyl fragments or molecules, bonds to 'inorganic' carbon, such as those to carbon monoxide (metal carbonyls), cyanide, or carbide, are also typically regarded as organometallic. Although they are not strictly speaking organometallic compounds, some similar compounds, such as transition metal hydrides and metal phosphine complexes, are frequently included in discussions of such substances. The phrase "metalorganic compound," which is comparable but different, describes molecules that contain metals but do not have direct metal-carbon bonds but do have organic ligands.

Learn more about organometallic reagent here:

brainly.com/question/13299409

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4 0
2 years ago
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Elza [17]

Answer: There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{63.00g}{18g/mol}=3.5moles

1 mole of H_2O contains =  6.023\times 10^{23} molecules

Thus 3.5 moles of H_2O contains =  \frac{6.023\times 10^{23}}{1}\times 3.5=21.08\times 10^{23} molecules.

There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

3 0
3 years ago
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