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3 years ago

One mole of N2 gas at STP will occupy what volume?

Chemistry

2 answers:

Sergio [31]3 years ago

8 0

Answer:

If you have 1 mole of N2 (or any other gas for that matter) under STP conditions it will occupy a volume of 22.4 L. This is known as the “standard molar volume”. So, if you know the number of moles of gas that you have, you can use a simple ratio (1 mole : 22.4 L) to determine the volume of the gas

Explanation:

maksim [4K]3 years ago

5 0

Answer:

One mole of N2 gas at STP will occupy 22.4 L.

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

So, if you have 1 mole of the N2 gas under STP conditions, it means that this gas will occupy a volume of 22.4 L.

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ValentinkaMS [17]

Answer : The concentration of $OH^-$ ion, pH and pOH of solution is, $1.12\times 10^{-13}M$ , 1.05 and 12.95 respectively.

Explanation : Given,

Concentration of $H^+$ ion = 0.090 M

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

The expression used for pH is:

$pH=-\log [H^+]$

First we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (0.090)$

$pH=1.05$

The pH of the solution is, 1.05

Now we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-1.05=12.95$

The pOH of the solution is, 12.95

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$12.95=-\log [OH^-]$

$[OH^-]=1.12\times 10^{-13}M$

The $OH^-$ concentration is, $1.12\times 10^{-13}M$

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2 years ago

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DochEvi [55]

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dsp73

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Explanation:

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