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Neko [114]
3 years ago
13

Four different methods are described for validating the results of a particular analysis. Indicate for each whether the method p

rimarily checks the accuracy of the analysis or the precision of the analysis.
(A) Five aliquots of the same sample are injected for gas chromatographic analysis by one person on the same day
(B) A known amount of analyte is added to an aliquot of the sample and analyzed with sample
(C) Aliquots from a blood sample are sent to three separate laboratories for analysis using the same method.
(D) Identical standard are analyzed by two different methods.
Chemistry
1 answer:
il63 [147K]3 years ago
7 0

Answer:

A) Precision

B) Accuracy

C) Precision

D) Accuracy

Explanation:

<em>Accuracy</em> and <em>Precision </em>are factors that determine whether a given analysis is appropiate or not.

Accuracy refers to how close the experimental result is to a <em>known, theoretical or accepted value. </em>For this reason every method that checks the accuracy uses a standard -this could mean repeating the test using the standard instead of the sample, or adding a known amount of analyte to the sample-, in order to compare the results.

Precision refers to how close repeated the results of different tests are to each other, in other words, it refers to the <em>repeatability </em>of the method. A test for precision would require that the method is done several times, in order to check how close the results are to each other, regardless of whether those results are close to the expected value.

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To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

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\frac{P_1}{T_1}=\frac{P_2}{T_2}

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P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=149kPa\\T_1=-14^0C=(273-14)=259K\\P_2=?=27.5psi\\T_2=17.3^0C=(273+17.3)=290.3K

Putting values in above equation, we get:

\frac{149}{259}=\frac{P_2}{290.3}\\\\P_2=167kPa

Hence, the pressure after the tire is heated to 17.3°C is 167 kPa

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