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Neko [114]
3 years ago
13

Four different methods are described for validating the results of a particular analysis. Indicate for each whether the method p

rimarily checks the accuracy of the analysis or the precision of the analysis.
(A) Five aliquots of the same sample are injected for gas chromatographic analysis by one person on the same day
(B) A known amount of analyte is added to an aliquot of the sample and analyzed with sample
(C) Aliquots from a blood sample are sent to three separate laboratories for analysis using the same method.
(D) Identical standard are analyzed by two different methods.
Chemistry
1 answer:
il63 [147K]3 years ago
7 0

Answer:

A) Precision

B) Accuracy

C) Precision

D) Accuracy

Explanation:

<em>Accuracy</em> and <em>Precision </em>are factors that determine whether a given analysis is appropiate or not.

Accuracy refers to how close the experimental result is to a <em>known, theoretical or accepted value. </em>For this reason every method that checks the accuracy uses a standard -this could mean repeating the test using the standard instead of the sample, or adding a known amount of analyte to the sample-, in order to compare the results.

Precision refers to how close repeated the results of different tests are to each other, in other words, it refers to the <em>repeatability </em>of the method. A test for precision would require that the method is done several times, in order to check how close the results are to each other, regardless of whether those results are close to the expected value.

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nikdorinn [45]

Answer:

<h2>2.44 L</h2>

Explanation:

The volume can be used by using the formula for Boyle's law which is

P_1V_1 = P_2V_2 \\

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Since we're finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

We have

V_2 =  \frac{2.5 \times 4.4}{4.5}  =  \frac{11}{4.5}  \\  = 2.444444....

We have the final answer as

<h3>2.44 L</h3>

Hope this helps you

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A compound is 40% carbon, 6.7% hydrogen, and 53.3% oxygen. What is the empirical formula?
Ahat [919]

Answer:

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The solubility of nitrogen gas at 25 degrees C and 1 atm is 6.8 x 10^(-4) mol/L. If the partial pressure of nitrogen gas in air
Zolol [24]

Answer:

5.2 x 10⁻⁴ M.

Explanation:

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<em>P = kC</em>

where P is the partial pressure of the gaseous  solute above the solution.

k is a constant (Henry’s constant).

C is the concentration of the dissolved gas.

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<em>∴ C₂ = (P₂C₁)/P₁ =</em> (0.76 atm)(6.8 x 10⁻⁴ mol/L)/(1.0 atm) = <em>5.168 x 10⁻⁴ mol/L ≅ 5.2 x 10⁻⁴ M.</em>

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