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Vlada [557]
4 years ago
5

A bicyclist is moving toward a sheer wall while holding a tuning fork rated at 488 Hz. 1) If the bicyclist detects a beat freque

ncy of 8 Hz (between the waves coming directly from the tuning fork and the echo waves coming from the sheer wall), calculate the speed of the bicycle. Assume the speed of sound is 343 m/s.
Physics
1 answer:
gayaneshka [121]4 years ago
6 0

Answer:

speed of the bicycle = 2.81 m/s

Explanation:

given data

tuning fork rated f = 488 Hz

beat frequency fb = 8 Hz

speed of sound vs = 343 m/s

solution

we get here frequency that rider is listening that is

rider hearing frequency = 488 Hz + 8 Hz

rider hearing frequency = 496 Hz

and when it bouncing from sheer wall at frequency of related to stationary object

frequency = 488 Hz + 4 Hz

frequency =  492 Hz

so now we get speed of the bicycle that is

speed of the bicycle =  (  \frac{492}{488} × 343 )  - 343 Hz

speed of the bicycle = 2.81 m/s

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A 3.00 kg object is fastened to a light spring, with the intervening cord passing over a pulley. The pulley is frictionless, and
finlep [7]

Answer:

Part a)

k = 588.6 N/m

Part b)

v = 0.7 m/s

Explanation:

As we know that initially block is at rest

now if block is released from rest then it will go down by 10 cm and again comes to rest

so here we have

Part a)

Work done by gravity + work done by spring force = change in kinetic energy

W_g + W_{spring} = 0 - 0

mg(0.10) + \frac{1}{2}k(0^2 - 0.10^2) = 0

3(9.81)(0.10) - \frac{1}{2}k(0.10)^2 = 0

k = 588.6 N/m

Part b)

Now when spring is stretch by x = 5 cm then the speed of the block is given as

mgx' + \frac{1}{2}k(0^2 - x'^2) = \frac{1}{2}mv^2 - 0

here we have

x' = 0.05 m

3(9.81)(0.05) - \frac{1}{2}(588.6)(0 - 0.05^2) = \frac{1}{2}(3) v^2

1.4715 - 0.736 = 1.5 v^2

v = 0.7 m/s

3 0
3 years ago
Refer to Activity 1: Describe the difference between the rate of diffusion seen for urea and albumin
raketka [301]

Answer:

the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin.

Explanation:

As described in activity 1, the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin. Urea basically is an heavy compound, thus it is at the base of the chain reactions  which which major purpose is to break down the amino acids that make up proteins. Albumin on the other hand is a form of protein that simply helps in the transmission of blood and prevent blood from flowing through to other tissue in the body. The liver produces the albumin the body. So going back to the question, the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin.

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Answer:2H2O2 → 2H2O + O2

Explanation:

For a chemical equation to be balanced, the number of moles of each element at the reactant must be equal to that of the product.

According to the equation given

H2O2 → H2O + O2

There are two hydrogen atoms with two oxygen atoms at the reactant and 2hydrogen and 3oxygen at the product which shows the equation is not balanced. To balance this,

We will add 2 moles to H2O2 at the reactant and 2 moles to H2O at the product to give;

2H2O2 → 2H2O + O2 (Balanced equation)

As we can see that we now have 4 moles of Hydrogen and 4 moles of oxygen at both reactant and product making the equation balanced.

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An electric field of 6.1x 10^5 N/C is directed along a charge 2.9 x 10^-19 C. What
Aloiza [94]

Answer:

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3 years ago
Which major planet has the largest . . . A. semimajor axis? B. average orbital speed around the Sun? C. orbital period around th
Yuliya22 [10]
<h2>Mercury, Neptune, and Jupiter </h2>

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  • Neptune has the longest orbital speed around the sun of any planet in the Solar System which is equivalent to 164.8 years (or 60,182 Earth days)
  • Jupiter has the largest eccentricity.

Hence, the answer is Mercury, Neptune, and Jupiter respectively.

6 0
4 years ago
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