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Anit [1.1K]
3 years ago
6

Please help me with this (with explanation)

Physics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

Suppose the cyclist travels for a total time of <em>t</em> hours.

For 20 min = 1/3 hr, the cyclist does not move.

Over the remaining (<em>t</em> - 1/3) hr, the cyclist is moving at a constant speed of 22.0 km/hr, so that the cyclist would travel a distance of

<em>x</em> = (22.0 km/hr) • ((<em>t</em> - 1/3) hr) ≈ (22.0 km/hr) <em>t</em> - 7.33 km

If the cyclist's average speed over the total time <em>t</em> was 17.5 km/hr, then by the definition of average speed,

17.5 km/hr = <em>x</em> / <em>t</em>

Replace <em>x</em> with the distance expression from earlier:

17.5 km/hr = ((22.0 km/hr) <em>t</em> - 7.33 km) / <em>t</em>

Solve for <em>t</em> :

17.5 km/hr = 22.0 km/hr - (7.33 km) / <em>t</em>

(7.33 km) / <em>t</em> = 4.5 km/hr

<em>t</em> = (7.33 km) / (4.5 km/hr)

<em>t</em> ≈ 1.62963 hr

Then the distance the cyclist traveled must have been

<em>x</em> ≈ (22.0 km/hr) (1.62963 hr) - 7.33 km ≈ 28.5 km

and so the answer is A.

Alternatively, as soon as you arrive at

17.5 km/hr = <em>x</em> / <em>t</em>

you can instead solve for <em>t</em> in terms of <em>x</em>, then plug that into the distance equation.

<em>t</em> = <em>x</em> / (17.5 km/hr)

then

<em>x</em> ≈ (22.0 km/hr) (<em>x</em> / (17.5 km/hr)) - 7.33 km

<em>x</em> ≈ 1.25714 <em>x</em> - 7.33 km

0.25714<em>x</em> ≈ 7.33 km

<em>x</em> = (7.33 km) / 0.25714 ≈ 28.5 km

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Solution :

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Therefore,

90 revolutions in 1 minute

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7 0
2 years ago
The planet Saturn has a mass that is 95 times Earth's mass and a radius that is 9.4 times Earth's radius. What is the accelerati
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10.55111 m/s²

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Acceleration due to gravity is given by

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4 0
3 years ago
Temperature change time base problem. Suppose V = 24 V, I = 0.1 A, for water: mw = 51 gm, cw = 4.18 J/gm ∘K-1, for resistor: mr
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Answer:

t = 444.125 sec

Explanation:

Given data:

V = 24 volt

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mass of resistor = 8 gm

cr = 3.7 J/gm degree K^-1

we know that power is given as

Power P = VI

But P =E/t

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\frac{E}{t} = VI

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t = \frac{E}{VI}

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t = \frac{51 \times 4.18 \times (5 -0)}{24\times 0.1}

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5 0
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zepelin [54]

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As such, since the sphere has a smaller surface area relative to the cylinder, the sphere transfers heat slower than the cylinder.

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