Answer:
Explanation:
Hello!
In this case, since the ionization of ammonia, which is a weak base, is written as:
We can see that the ammonium ion is the conjugate acid whereas the hydroxide ions the conjugate base; that is why we use the Henderson-Hasselbach equation to compute the pH, given the pKb of ammonia 4.75:
![pH=pKb+log(\frac{[conj\ acid]}{[base]} )](https://tex.z-dn.net/?f=pH%3DpKb%2Blog%28%5Cfrac%7B%5Bconj%5C%20acid%5D%7D%7B%5Bbase%5D%7D%20%29)
In such a way, for the given moles of ammonia, base, and those of ammonium chloride, conjugate acid form, we obtain:
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Answer:
It would increase the final quantity of products
Explanation:
According to the Le- Chatelier principle,
At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.
The equilibrium can be disturb,
By changing the concentration
By changing the volume
By changing the pressure
By changing the temperature
Consider the following chemical reaction.
Chemical reaction:
2NO₂ ⇄ N₂O₄
In this reaction the equilibrium is disturb by increasing the concentration of reactant.
When the concentration of reactant is increased the system will proceed in forward direction in order to regain the equilibrium. Because when reactant concentration is high it means reaction is not on equilibrium state. As the concentration of NO₂ increased the reaction proceed in forward direction to regain the equilibrium state and more product is formed.
Answer: ?
Explanation: I translated this and It makes no sense.
Tôi đã dịch điều này và nó không có ý nghĩa.
Answer:
a. At pH 9, the product, p-nitrophenol, will be ionized, the solution will appear yellow in color, and thus can be monitored at the wavelength of maximum absorption for the phenolate ion which is 400nm
Explanation:
In alkaline phosphatase assay, the hydrolysis of p nitrophenyl phosphate to p nitrophenol happens. When the ph is 9, the product which is p nitrophenol would undergo ionization. The solution is going to appear to be of yellow and it can be monitored at a wavelength for maximum absorption of phenolate ions at 400nm.
Option A is the answer to the question.
