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Pepsi [2]
2 years ago
15

PLEASE HELP AND DONT YOU DARE GIVE ME THE LINK

Chemistry
1 answer:
IgorLugansk [536]2 years ago
3 0

Answer:

animals and other living things

Explanation:

All living organisms have been classified and grouped into a hierarchical system of classification. Kingdom is the highest level in this system comprising of 6 other levels. However, there are different kingdoms that harbors different organisms. The kingdoms are: animalia, plantae, protista, monera, fungi etc.

However, among other kingdom of organisms, organisms in the Kingdom Animalia are the only ones that possesses muscle tissues etc. This shows a contrast between animals and other living things.

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Which term can be used to describe the process in the reaction below? 2 NaHCO3 (s) → Na2CO3 (s) + H2O (g) + CO2 (g)
Setler79 [48]

Answer:

Decomposition

Explanation:

If we look at the process;

2 NaHCO3 (s) → Na2CO3 (s) + H2O (g) + CO2 (g)

We can see that NaHCO3 was broken down into Na2CO3, H2O and CO2.

The breakdown of one compound to yield other chemical compounds is known as decomposition.

Hence the NaHCO3 was decomposed in the process above.

4 0
2 years ago
Plants use sunlight from the atmosphere during the process of
Nastasia [14]

Answer:

photosynthesis

Explanation:

6 0
2 years ago
Read 2 more answers
Be sure to answer all parts. Express the rate of reaction in terms of the change in concentration of each of the reactants and p
Tanzania [10]

Answer :  The [H] is increasing at the rate of 0.36 mol/L.s

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

2D(g)+3E(g)+F(g)\rightarrow 2G(g)+H(g)

The expression for rate of reaction :

\text{Rate of disappearance of }D=-\frac{1}{2}\frac{d[D]}{dt}

\text{Rate of disappearance of }E=-\frac{1}{3}\frac{d[E]}{dt}

\text{Rate of disappearance of }F=-\frac{d[F]}{dt}

\text{Rate of formation of }G=+\frac{1}{2}\frac{d[G]}{dt}

\text{Rate of formation of }H=+\frac{d[H]}{dt}

\text{Rate of reaction}=-\frac{1}{2}\frac{d[D]}{dt}=-\frac{1}{3}\frac{d[E]}{dt}=-\frac{d[F]}{dt}=+\frac{1}{2}\frac{d[G]}{dt}=+\frac{d[H]}{dt}

Given:

-\frac{d[D]}{dt}=0.18mol/L.s

As,  

-\frac{1}{2}\frac{d[D]}{dt}=+\frac{d[H]}{dt}=0.18mol/L.s

and,

+\frac{d[H]}{dt}=2\times 0.18mol/L.s

+\frac{d[H]}{dt}=0.36mol/L.s

Thus, the [H] is increasing at the rate of 0.36 mol/L.s

5 0
3 years ago
A small motor does 4000 J of work in 20 s. What is the power of the motor in watts?
TEA [102]

Answer:

200 W

Explanation:

Formula of Power is

P= W/T

where

W= Work and T= Time

so

4000/20 = 200J/s or 200 W

6 0
2 years ago
the pressure of 5.0 L of gas increases from 1.50atm to 1240 mmgh. what is the final volume of the gas, assuming no change in mol
NikAS [45]

Answer:

V₂ = 4.7 L

Explanation:

Given data:

Initial volume = 5.0 L

Initial pressure = 1.50 atm

Final pressure = 1240 mmHg (1240/760 = 1.6 atm)

Final volume = ?

Solution:

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = 1.50 atm ×5.0 L/1.6 atm

V₂ = 7.5 atm. L /1.6 atm

V₂ = 4.7 L

6 0
2 years ago
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