An object in uniform circular motion must be changing its speed in order move in a circular path

Physics

1 answer:

mafiozo [28]3 years ago

8 0

Answer:

False

Explanation:

An object in uniform circular motion must be changing its velocity in order to move in a circular path.

In fact, remind that velocity is a vector which consists of a magnitude (the speed) and a direction.

When an object is moving in uniform circular motion, the direction of the motion is constantly changing (since the trajectory is a circle): so, this means that the velocity is also changing. However, this does not imply that the speed of the object is changing. In fact, in a uniform circular motion, the speed of the object remains constant.

You might be interested in

Green plants need light in order to survive. Structures in the leaves absorb light, which in turn, helps plants make their own f

Goryan [66]

The answer is green.

3 0

3 years ago

Read 2 more answers

Two charges of +4x10-SC and -4x10-5C are placed 1 meter apart. Using Coulomb's law, the force between them is 14.4 N.

Snowcat [4.5K]

Answer:

d. the force is reduced by one quarter to 3.6 n

Explanation:

6 0

2 years ago

Summarize Newton's three laws of motion

Sedaia [141]

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

7 0

3 years ago

You are on your balcony and notice some bad squirrels digging in your garden directly below. You start tossing your pistachios a

Rashid [163]

Answer:

0.43 s

Explanation:

We have the following parameters:

Initial velocity, u = 7.4 m/s

Acceleration of gravity, g = 9.8 $m/s^2$

Distance, s = 43 in + 10 ft = 1.092 m + 3.048 m = 4.14 m

Time, t = ?

Using the equation of motion $s=ut +\frac{1}{2}gt^2$ , we have

$4.14 = 7.4t + 0.5\times9.8t^2$

$4.9t^2 + 7.4t - 4.14 =0$

Using the quadratic formula $\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$ where a = 4.9, b = 7.4 and c = - 4.14, and solving for the positive value of t only, we have