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3 years ago

Calculate the work associated with the compression of a gas from 121.0 L to 80.0 L at a constant pressure of 16.7 atm.

Chemistry

1 answer:

Mkey [24]3 years ago

4 0

Answer:

6.94 × 10⁴ J

Explanation:

We can calculate the work (W) associated with the compression of a gas at constant pressure using the following expression:

W = -P . ΔV

where,

P is the external pressure

ΔV is the change in the volume

Knowing that 1 atm.L = 101.325 J, the work of compression is:

$W=-P\times \Delta V=-16.7atm\times(80.0L-121.0L)\times\frac{101.325J}{1atm.L} =6.94\times10^{4} J$

The positive sign of the work means that the surroundings do work on the system.

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1e569^4b is the answer

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3 years ago

Which substance do plants use to capture light energy from the sun? a) Carbon dioxide b) Chlorophyll c) Glucose d) Oxygen

Akimi4 [234]

Answer: chlorophyll

Explanation:

The substance that plants use to capture light energy from the sun is referred to as chlorophyll.

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3 years ago

Read 2 more answers

How many minutes will it take to plate out 4.50 g of Cu from a solution of Cu(NO3)2 (aq) onto the cathode of an electrolytic cel

ipn [44]

Answer:

It will take 28.5 minutes

Explanation:

<u>Step 1: </u>Data given

Mass of Cu = 4.50 grams

8.00 A of current are used

Molar mass of Cu = 63.5 g/mol

Step 2: Calculate time needed

Cu2+ →Electricity → Cu

we notice a flow of 2 electrons ⇒ This means the Faraday constant = 2F

Since Molar mass of Cu is 63.5 g/mol

63.5 grams of Cu is deposited by 2*96500 C

4.50 grams of Cu ((2*96500)/63.5) * 4.50 = 13677.17 C

Q = It

13677.17 = 8t*60 seconds

t = 28.5 minutes

3 0

3 years ago

Which solution would have the lowest freezing point

Vitek1552 [10]

Answer:

Ice and water

Explanation:

4 0

3 years ago

The fact that HBO2, a reactive compound, was produced rather than the relatively inert B2O3 was a factor in the discontinuation

Reil [10]

Answer:

1027.62 g

Explanation:

For $B_2H_6$ :-

Mass of $B_2H_6$ = 296.1 g

Molar mass of $B_2H_6$ = 27.66 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{296.1\ g}{27.66\ g/mol}$

$Moles\ of\ B_2H_6= 10.705\ mol$

From the balanced reaction:-

$B_2H_6(g) + 3 O2_{(l)}\rightarrow 2 HBO_2_{(g)}+ 2 H_2O_{(l)}$

1 mole of $B_2H_6$ react with 3 moles of oxygen

Thus,

10.705 mole of $B_2H_6$ react with 3*10.705 moles of oxygen

Moles of oxygen = 32.115 moles

Molar mass of oxygen gas = 31.998 g/mol

<u>Mass = Moles * Molar mass = 32.115 * 31.998 g = 1027.62 g</u>

8 0

3 years ago