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goldfiish [28.3K]
3 years ago
15

In a single-slit diffraction experiment, the width of the slit through which light passes is increased. What happens to the widt

h of the central bright fringe?
Physics
1 answer:
kvasek [131]3 years ago
3 0

Answer:

the width of the central bright fringe reduces

Explanation:

In a single-slit diffraction experiment, if the width of the slit through which light passes is increased, then the width of the central bright fringe reduces.

Example, if the width of the slit is doubled, then the width of the central bright fringe will be halved.

Thus, for single-slit diffraction experiment, increase in the width of the slit through which light passes will result in a corresponding decrease in the width of the central bright fringe.

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Which of the following varies as the electric current varies? The magnetic force decreases The magnetic properties are varied Th
Paladinen [302]
The magnetic properties are varied
6 0
4 years ago
Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t
Readme [11.4K]

Answer: 3.66(10)^{33}kg

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity \omega of the planet P1 with a period T=750years=2.36(10)^{10}s:

\omega=\frac{2\pi}{T}=\frac{V_{1}}{R} (1)

Where:

V_{1}=40.2km/s=40200m/s is the velocity of planet P1

R is the radius of the orbit of planet P1

Finding R:

R=\frac{V_{1}}{2\pi}T (2)

R=\frac{40200m/s}{2\pi}2.36(10)^{10}s (3)

R=1.5132(10)^{14}m (4)

On the other hand, we know the gravitational force F between the star S with mass M and the planet P1 with mass m is:

F=G\frac{Mm}{R^{2}} (5)

Where G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

In addition, the centripetal force F_{c} exerted on the planet is:

F_{c}=\frac{m{V_{1}}^{2}}{R^{2}} (6)

Assuming this system is in equilibrium:

F=F_{c} (7)

Substituting (5) and (6) in (7):

G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}} (8)

Finding M:

M=\frac{V^{2}R}{G} (9)

M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}} (10)

Finally:

M=3.66(10)^{33}kg (11) This is the mass of the star S

4 0
4 years ago
Optics of the eye: the closest object that a typical young person with normal vision can focus on clearly is closest to:______.
Natali [406]

The human eye is one of the most valuable sense organ. The closest object that a typical young person with normal vision can focus closest to is 25 cm

The lens in the eye forms the image on the retina. The image formed is real and inverted. The retina is a very delicate membrane containing numerous light sensitive cells.

This light sensitive cells gets activated when light falls on it and generates electric signals. These electric signals are sent to the brain via the optic nerves present in the eye. The brain finally processes these signals and thus we see the object clearly.

The ability of the lens of the eye to adjust its focal length accordingly is called the power of accommodation,

The minimum distance, at which the object can be seen clearly without any strain is called the least distance of distinct vision.

To see an object clearly without any strain is when we place it at about 25 cm from the eye.

Tolearn more about optics of the eye : brainly.com/question/22371574

#SPJ4

5 0
2 years ago
T or F-Climate is directly related to the amount of energy from the sun or solar energy that an area receives
____ [38]

Answer:

true

Explanation:

the sun warms the atmosphere and warms the air which drives our weather

8 0
3 years ago
Spiderman has a mass of 80 kg. He knows his webbing will break if it is exposed to a 200 N force. What is the maximum height he
likoan [24]

Answer:

This depends on the writers

if they want they can make spiderman deny the laws of nature

8 0
3 years ago
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