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Leni [432]
4 years ago
14

H2 + NO → H2O + N2 If 180.5 grams of N2 are produced, how many grams of H2 were reacted?

Chemistry
1 answer:
Lena [83]4 years ago
6 0

Answer:

12.89 moles

Explanation:

Before we solve the question, we have to balance the equation of the reaction first. The balanced reaction will be:

2 NO + 2 H2→ N2 + 2 H2O

There are 180.5g of N2 produced, the number of produced in moles will be: 180.5g / (28g/mol)= 6.446 moles

The coefficient of H2 is two and the coefficient of N2 is one. Mean that we need two moles of H2 for every one mole of N2 produced. The number of H2 reacted will be: 2/1 * 6.446 moles = 12.89 moles

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Word equation for <br> Zn + 2HCI - ZnCl2 + H2
Alborosie

Answer:

zinc reacts with 2 moles of hydrochloric acid to produce two moles of zinc(ii) chloride and hydrogen gas

Explanation:

please like and Mark as brainliest

7 0
4 years ago
Find the number of Li atoms in 1.50 mole of Li
ale4655 [162]
The molar mass of Li->7g/mol
If 1mol of Li is 7g/mol
1.50mol of Li would be 10.5g/mol
7 0
3 years ago
Carbon disulfide burns in oxygen to yield car- bon dioxide and sulfur dioxide according to the chemical equation cs2(l) 3 o2(g)
vampirchik [111]

Answer: Oxygen is the limiting reagent.

Explanation: CS_2(l)+3O_2(g)\rightarrow CO_2(g)+2SO_2(g)

As can be seen from the given balanced equation:

3 moles of O_2 reacts with 1 mole of CS_2

1.52 moles of O_2 reacts with=\frac{1}{3}\times 1.52=0.51moles of CS_2

Thus O_2 is the limiting reagent as it limits the formation of products. (0.91-0.51)= 0.40 moles of CS_2 will remain as such and thus  CS_2 is an excess reagent.

6 0
3 years ago
Becoming a physicist involves studying various subject matter, besides physics what subjects should be studied in college?​
atroni [7]

Answer:

Crystallography, nanotechnology, biophotonics, condensed matter theory and solar energy.

Explanation:

Some other subjects that should be studied in college are crystallography, nanotechnology, biophotonics, condensed matter theory ,and solar energy. These may help you in the studying of a physicist.

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3 0
3 years ago
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. the initial temperature of the gas is 27.0c
Alla [95]

We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.

The final temperature is: 75.11 °C.

The work done at constant pressure, W=nR(T₂-T₁)

n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).

W=2.4 × 10³ Joule (Given)

From the expression,

(T₂-T₁)=\frac{W}{nR}

(T₂-T₁)= \frac{2.40 X 10^{3} }{6 X 8.314}

(T₂-T₁)= 48.11

T₂=300+48.11=348.11 K= 75.11 °C

Final temperature is 75.11 °C.


6 0
3 years ago
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